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3 years ago

Factor out each polynomial 25x^2 - 1

Mathematics

1 answer:

agasfer [191]3 years ago

8 0

(5x+1)(5x-1) tell me if you want to know how to do this problem :)

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The question is above in the picture, please help!

Evgen [1.6K]

Answer:

cef

Step-by-step explanation:

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2 years ago

fred can complete a work in 6 days and Paul can complete a work in 3 days. if fred and Paul work together, how many days can the

defon

Answer:

I think its 3 or 2 days bc if paul can get two works done by the time fred can get one done then the days should be divided.

Step-by-step explanation:

3 0

2 years ago

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are:

$\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\ \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Answer: Third option

8 0

1 year ago

The points (2, 3) and (6, 11) lie on a line. What is the slope of this line?

AveGali [126]

Answer:

8/4

Step-by-step explanation:

to do slope is y2 - y1 over x2 - x1, so it would be 11 - 3 for 8, then 6 - 2, leaving 8/4.

3 0

3 years ago

A group of 20 students are going to watch a basketball game. It cost $10 for 4 students to watch a game. How much will the group

ivolga24 [154]

They will pay 15 dollars

6 0

2 years ago