The sum of the first 7 terms of the geometric series is 15.180
<h3>Sum of geometric series</h3>
The formula for calculating the sum of geometric series is expressed according to the formula. below;
GM = a(1-r^n)/1-r
where
r is the common ratio
n is the number of terms
a is the first term
Given the following parameters from the sequence
a = 1/36
r = -3
n = 7
Substitute
S = (1/36)(1-(-3)^7)/1+3
S = 1/36(1-2187)/4
S = 15.180
Hence the sum of the first 7 terms of the geometric series is 15.180
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let the equation be
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G(x)=-(x^2-6x+5)
=-(x-6x+9-9+5)
=-(x-3)²+4
It is reflected across the a axis, shifted 3 units to the right, shifted 4 units up, and It has an axis of symmetry at x=3
Answer:
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Answer:
Common difference is 3. And the first term is 64.
Step-by-step explanation:
The differnce between 21 and 10 is 11. So there are 11 unknown numbers in between. And the difference between 37 and 4 is 33. 33/11 is equal to 3. So the pattern is minus three. the first term is 9 terms before 37. 9 times 3 is 27. 37+27 is equal to 64. so the first term is 64
