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3 years ago

Find the solution of this system of equations. Separate the x- and y- values with a comma. x-2y=-24 and x-y=4

1 answer:

defon3 years ago

6 0

X - 2y = -24
x - y = 4

Isolate x in the first equation by adding 2y to both sides.
x = -24 + 2y

Now plug in this value of x into the second equation.
(-24 + 2y) - y = 4
Solve. Combine all like terms, 2y - y.
-24 + y = 4
Add 24 to both sides to isolate y.
y = 28

Now plug y back into the first equation to find x.
x - 2(28) = -24
x - 56 = -24
Add 56 to both sides to isolate x.
x = 32

The solution is (32, 28).

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A store sells 3 cans of beans for $9. What is the price of 7 cans of beans?

Leokris [45]

Answer:

Step-by-step explanation:

because you divide 9 byy 3 and you get 3 so then you do 7 x 3 7x3 is 21

8 0

3 years ago

What is the value of A when we rewrite... (PLZ HELP QUICK)

Marina86 [1]

Answer:

Step-by-step explanation:

Given,

${( \frac{5}{2} )}^{x} + {( \frac{5}{2} )}^{x + 3}$

$= {( \frac{5}{2}) }^{x} + {( \frac{5}{2}) }^{x} \times {( \frac{5}{2} )}^{3}$

$= ( \frac{5}{2} ) ^{x} (1 + {( \frac{5}{2} )}^{3}$

$= {( \frac{5}{2} )}^{x} (1 + \frac{125}{8} )$

$= {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )$

$= {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )$

${( \frac{5}{2} )}^{x} ( \frac{133}{8} )$

Comparing with A • ${( \frac{5}{2}) }^{x}$

A = $\frac{133}{8}$

Hope this helps...

Good luck on your assignment...

7 0

3 years ago

Can someone help me the 2nd problem I don’t understand it

Galina-37 [17]

Answer:

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

270 miles

Step-by-step explanation:

So is A is going faster than B so A will reach the destination first.

When will A reach it's destination?

Let's find out.

To solve this problem, the following will come in handy:

Speed=distance/time or time*Speed=distance or time=distance/speed .

time=distance/speed

$T_A=\frac{390}{S_A}$

$T_A=\frac{390}{65}$

$T_A=6$

So it will take bus A 6 hours to cover the distance of 390 miles.

How much time would have it taken bus B to reach that same distance?

$T_B=\frac{390}{45}$

$T_B=8.\overline{6}$

So it would have taken bus B $8.\overline{6}$ hours to cover a distance of 390 miles.

So the time difference is $8.\overline{6}-6=2.\overline{6}$ hours.

It will take $2.\overline{6}$ more hours than bus A for bus B to complete a distance of 390 miles.

So bus B traveled $2.\overline{6} \cdot 45=120$ miles (used the time*speed=distance) after bus A got to it's destination.

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

4 0

3 years ago

Based on the Pythagorean Theorem, which of

aleksley [76]

Answer:

G is not TRUE.

Step-by-step explanation:

using the law A+B = B+A

PYTHAGOREAN THEOREM

A²+B² =C² is equal to B² +A² = C²

So for A²,

B² - c² = A. remember if a positive number move from the left to the right over an equal sign it becomes negative and vice versa

B²

C² - A²= B²

6 0

2 years ago

how many 4 digit numbers n have the property that the 3 digit number obtained by removing the leftmost digit is one ninth of n

Tom [10]

Answer:

Step-by-step explanation:

We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.

Let the thousands digit be 'd'. Then we want to find the integer solutions to ...

n -1000d = n/9

n -n/9 = 1000d . . . . . . add 1000d -n/9

8n = 9000d . . . . . . . . multiply by 9

n = 1125d . . . . . . . . . divide by 8

The values of d that will give a suitable 4-digit value of n are 1 through 7.

When d=8, n is 9000. Removing the 9 gives 0, not 1000.

When d=9, n is 10125, not a 4-digit number.

There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.

8 0

2 years ago