<span>(7 x 10^−12)(4 x 10^5)
= (7x4) x 10^-7
= 28 x 10^-7
= 2.8 x 10^-6</span>
Given:
The figure of two parallel lines MP and QS.
A transversal line KL interests the two parallel lines.
![m\angle KNM =146^\circ](https://tex.z-dn.net/?f=m%5Cangle%20KNM%20%3D146%5E%5Ccirc)
To find:
The
.
Solution:
If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.
In the given figure
and
corresponding angles. It means their measures are equal.
![m\angle KRQ=m\angle KNM](https://tex.z-dn.net/?f=m%5Cangle%20KRQ%3Dm%5Cangle%20KNM)
![m\angle KRQ=146^\circ](https://tex.z-dn.net/?f=m%5Cangle%20KRQ%3D146%5E%5Ccirc)
Therefore,
.
Put the values of the variables in place of the variables in the expression, then do the arithmetic.
![8p+3q-18\\\\=8\left(\dfrac{1}{2}\right)+3(7)-18=\dfrac{8}{2}+21-18\\\\=4+21-18\\\\=25-18\\\\=\bf{7}](https://tex.z-dn.net/?f=8p%2B3q-18%5C%5C%5C%5C%3D8%5Cleft%28%5Cdfrac%7B1%7D%7B2%7D%5Cright%29%2B3%287%29-18%3D%5Cdfrac%7B8%7D%7B2%7D%2B21-18%5C%5C%5C%5C%3D4%2B21-18%5C%5C%5C%5C%3D25-18%5C%5C%5C%5C%3D%5Cbf%7B7%7D)
Answer:
42
Step-by-step explanation:
Let x = the original number of bushes in garden A
Let x-9 = the original number of bushes in garden B
x-9-3=x-12 = bushes in garden B after transplanting 3
x+3 = bushes in garden A after transplanting 3
x+3=1.5(x-12)
x+3=1.5x-18
0.5x=21
x=42
There were 42 current bushes in garden A
Answer:
Ur question is ununderstable
Step-by-step explanation: