So. let's say the numbers are "a" and "b"
whatever they're, we know a + b = 56
let's say the larger one is "b", so 3 times the smaller is 3*a or 3a
now, 12 less than that, is 3a - 12
and the larger is that, so b = 3a - 12
so
solve for "a", to see what the smaller one is
what's b? well, b = 56 - a
Answer:
120
Step-by-step explanation:
supplementary equal up 180
Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
25 because 5 times 5 is 25 im writing more because it has to be at least 20 characters
Firstly, we'll fix the postions where the 
women will be. We have 
forms to do that. So, we'll obtain a row like:
The n+1 spaces represented by the underline positions will receive the men of the row. Then,
Since there is no women sitting together, we must write that 
. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:
The equation (i) can be rewritten as:
We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: ![\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5B%28n%29%2B%28m-n%2B1%29%5D%21%7D%7B%28n%29%21%28m-n%2B1%29%21%7D%3D%5Cdfrac%7B%28m%2B1%29%21%7D%7Bn%21%28m-n%2B1%29%21%7D)
[I can write the proof if you want]
Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: 
Multiplying all results:
