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amm1812
3 years ago
7

(WILL AWARD BEST ANSWER) Is the relationship shown by the data linear? If so, model the data with an equation. (Data+Choices in

the attached picture)

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0
The relationship shown in this picture is linear. This can be determined by first looking at the x-column, and we can see that every value is continuously increasing by 4. Next, we look at the y-column, and we can see that each y-value is steadily increasing by 5. Since it is not increasing by a <u>factor</u> of 5, it is not exponential, it is linear. After we have determined this, we need to find the slope of the coordinates. To do this, we must take two coordinates - (1, 5) and (5, 10). Then, we need to plug in the respective values into the slope formula, giving us a slope of 5/4. Now, we take the first coordinate point in the table, (1, 5). Now, just put all the derived information into point-slope form, which gives us y - 5 = 5/4(x - 1). Therefore, the answer to your problem is B) The relationship is linear; y - 5 = 5/4(x - 1). Hope this helped!
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Makovka662 [10]
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4 0
3 years ago
Please show work! Thank you
xz_007 [3.2K]
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.

b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.

c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.

d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.

.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
4 0
2 years ago
Label the equations in number 5-7 as True or False:
kkurt [141]

Answer:

{ \rm{ {(7}^{1}) ^{9    }  = 7 {}^{5} \times  {7}^{5}  :   \: { \tt{ \red{false}}} }} \\{ \boxed{ \mathfrak{correction \dashrightarrow \: ( {7}^{1}) {}^{9}  =  {7}^{9}  }}} \\ \\  { \rm{ \frac{ {y}^{13} }{ {( {y}^{2}) }^{6} } =  {y}^{ - 10}   \times  {y}^{9}  :  \:{ \tt { \red{false}}}}} \\ { \boxed{ \mathfrak{correction \:  \dashrightarrow \:  { \rm{{y}^{1} }}}}} \\  \\ { \rm{ {b}^{4}  \times  {b}^{ - 6}  =   \frac{ {b}^{1}  \times  {b}^{3} }{ {b}^{6} } }} \:  :  \: { \tt{ \green{true}}}

8 0
2 years ago
Read 2 more answers
1. <br><br> Name the postulate or theorem you can use to prove the triangles congruent.
zzz [600]

Answer:

phthagoras

Step-by-step explanation:

7 0
2 years ago
Dave and Sandy Hartranft are frequent flyers with a particular airline. They often fly from City A to City B, a distance of 756
horsena [70]

Answer:

Plane = 441 mi/h; wind =  63 mi/h

Step-by-step explanation:

distance = rate × time

 Let p = the plane's speed in still air

and w = the wind speed . Then,

p + w = speed with wind

 p - w = speed against wind

We have two conditions:

(1)  756 = (p - w) × 2

(2) 756 = (p + w) × 1.5

Distribute the constants                  (3)    756 = 2p - 2w

                                                          (4)   756 = 1.5p + 1.5 w  

Multiply Equation (3) by 3                (5) 2268 = 6p  -  6w

Multiply Equation (4) by 4                (6) 3024 = 6p + 6w

Add Equations (5) and (6)                     5292 = 12p

Divide each side by 12                     (7)        p = 441 mi/h

Substitute (7) into Equation(3)                 756 = 882 - 2w

Add 2w to each side                      2w + 756 = 882

Subtract 756 from each side                    2w = 126

Divide each side by 2                                 w = 63 mph

The plane's speed in still air is 441 mi/h.

The wind speed is 63 mph.

Check:

(1) 756 = (441 - 63) × 2     (2) 756 = (441 + 63) × 1.5

   756 = 378 × 2                   756 = 504 × 1.5

   756 = 756                         756 = 756

8 0
3 years ago
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