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ozzi
3 years ago
8

Given H(6,7) and I(-7,-6), if point G lies 1/2 of the way along line segment HI, Santiago argues that point G is located at the

origin. Is Santiago correct? Justify your answer.
Mathematics
1 answer:
irinina [24]3 years ago
8 0

Given the points H(6,7) and I(-7,-6).

If point G lies \frac{1}{2} of the way along line segment HI.

Therefore, we can say that the point G divides the line segment HI in the ratio 1:1.

So, by using the cross section formula we can determine the coordinates of point G.

For the given points say (x_1, y_1) and (x_2, y_2) divided is in the ratio m_1 : m_2, the coordinates are (\frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} )

Coordinates G = (\frac{(1 \times -7)+(1 \times 6)}{2} , \frac{(1 \times -6)+(1 \times 7)}{2})

= (-0.5 , 0.5)

Hence, the coordinates of G are (-0.5 , 0.5).

So, Santiago argues that point G is located at the origin. The point G is located at (-0.5, 0.5). Therefore, he is not correct.

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Answer:

negative

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8 0
3 years ago
PT= 5x+3 and TQ= 48 midpoint of PQ is
prisoha [69]

Remark

This really can't be done unless you know that T is the midpoint. I'm pretty sure it is intended to be.

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8 0
2 years ago
Luis can spend up to $240 buying men’s and women’s shirts for his club. Men’s shirts cost $8 each and women’s shirts cost $12 ea
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4 0
3 years ago
Read 2 more answers
The given set together with the given operations is not a vector space. list the properties of the definition that fail to hold.
Triss [41]
Let us look at all the axioms of a vector space and see which axioms are broken. 
1) Associativity<span> of addition
</span>[(1,1)\bigoplus(2,2)]\bigoplus(3,3)=(6,6)
[(1,1)\bigoplus[(2,2)]\bigoplus(3,3)]=(6,6)<span>
It's trivial to see this one holds.
2)</span>Commutativity<span> of addition
</span>(1,1)\bigoplus(2,2)=(2,2)\bigoplus(1,1)=(3,3)
<span>This one holds.
3)</span>Identity element<span> of addition
</span><span>This means that we have zero vektor. It is pretty obvious we do, it is (0,0). 
</span>(a,b)\bigoplus(0,0)=(a,b)
4)Inverse elements<span> of addition
</span>This means that for each element in V there exists element -v such that v+(-v)=0. 
We do have inverse elements.
(a,b)\bigoplus(-a,-b)=(a-a,b-b)=0 
5)Compatibility<span> of scalar multiplication with field multiplication
</span>This one holds.
a[b(c,d)]=ab(c,d)
6)<span>Identity element of scalar multiplication
</span>Identity element of scalar multiplication is simply 1.
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7)Distributivity of scalar multiplication with respect to vector addition. Let's look at the definition.
a[(b,c)\bigoplus(d,e)]=a(b,c)\bigoplus a(d,e)
Now let's look at the example:
a[(1,1)\bigoplus(2,2)]=a(3,3)=(3,3a)
a(1,1)\bigoplus a(2,2)=(1,1a)\bigoplus(2,2a)=(3,3a)
This one hold too.
8)<span>Distributivity of scalar multiplication with respect to field addition
</span>Definition of this one is: 
(a+b)(c,d)=a(c,d)+b(c,d)
Let's take a look at the example:
(3+2)(1,2)=5(1,2)=(1,10)
(3+2)(1,2)=3(1,2)+2(1,2)=(1,6)+(1,4)=(2,10)
So this one doesn't hold.
The final answer would be distributivity of scalar multiplication with respect to field addition.
Please note vectors, in this case, are (a,b) and that I did not use the dot to indicate scalar multiplication.

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