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ozzi
3 years ago
8

Given H(6,7) and I(-7,-6), if point G lies 1/2 of the way along line segment HI, Santiago argues that point G is located at the

origin. Is Santiago correct? Justify your answer.
Mathematics
1 answer:
irinina [24]3 years ago
8 0

Given the points H(6,7) and I(-7,-6).

If point G lies \frac{1}{2} of the way along line segment HI.

Therefore, we can say that the point G divides the line segment HI in the ratio 1:1.

So, by using the cross section formula we can determine the coordinates of point G.

For the given points say (x_1, y_1) and (x_2, y_2) divided is in the ratio m_1 : m_2, the coordinates are (\frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} )

Coordinates G = (\frac{(1 \times -7)+(1 \times 6)}{2} , \frac{(1 \times -6)+(1 \times 7)}{2})

= (-0.5 , 0.5)

Hence, the coordinates of G are (-0.5 , 0.5).

So, Santiago argues that point G is located at the origin. The point G is located at (-0.5, 0.5). Therefore, he is not correct.

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5x³+8x²-7x-6
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Answer:


Step-by-step explanation:

Whether we divide using long division or using synthetic division, the rule is the same:  If, after division, there is no remainder (i. e., the remainder is zero), the divisor binomial is a factor or the associated root is indeed a root/zero/solution.

Divide 5x³+8x²-7x-6 by (x+2) using synthetic division.  Use the divisor -2 (which comes from letting x+2 = 0):

      --------------------------

-2   /    5    8    -7    -6

                -10    4     6

     ------------------------------

          5      -2    -3    0          Since the remainder here is 0, we know that

                                               -2 is a root of 5x³+8x²-7x-6 and that (x+2) is

                                                a factor of 5x³+8x²-7x-6.


Now check out the possibility that (x+1) is a factor of  5x^3 + 8x^2 - 7x - 6:

Use -1 as the divisor in synthetic division:    

        --------------------------

-1   /    5    8    -7    -6

                -5   -3     10

     ------------------------------

          5      3   -10    4        

Since there is a non-zero remainder (4), we can conclude that (x + 1) is NOT a factor of the given polynomial expression.  

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2 years ago
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Step-by-step explanation:

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Answer:

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