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harkovskaia [24]
3 years ago
12

Tony has twice as much money as Alicia. She has $16 less than Ralph. Together they all total $200. How much money does Tony have

?
Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Tony has $62

hope this helps :)

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Wayne Gretzky scored 50% more points than anyone else who ever played professional Hockey during his 20 seasons in the National Hockey League. He accomplished this amazing feat while playing in 280 fewer games than Gordy Howe, who is the previous record holder. The number of games he played during each season:
79,80,80,80,74 ,80,80,79,64,78,73,78,74,45,81,48,80,82,82,70.
a) The stem and leaf plot for the data can be comfortably obtained from the excel option as follows: XL STAT option in excel as follows:
1. In excel sheet choose XL STAT
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On the price is right game show, to get into the showcase at the end, contestants spins a wheel with 20 equally sized spaces, nu
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A) 9/20
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3 years ago
Asking again! Please solve! For both! Brainliest and lots of points!
Dennis_Churaev [7]

Answer:

1 D (10, 120)

2 C (20, 40)

Step-by-step explanation:

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Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.
alina1380 [7]

Answer:

v_1=(\frac{1}{10},-\frac{3}{10})

v_2=(-\frac{1}{10},\frac{3}{10})

Step-by-step explanation:

First we define two generic vectors in our \mathbb{R}^2 space:

  1. v_1 = (x_1,y_1)
  2. v_2 = (x_2,y_2)

By definition we know that Euclidean norm on an 2-dimensional Euclidean space \mathbb{R}^2 is:

\left \| v \right \|= \sqrt{x^2+y^2}

Also we know that the inner product in \mathbb{R}^2 space is defined as:

v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

\left \| v_1 \right \|= \sqrt{x^2+y^2}=1

and

\left \| v_2 \right \|= \sqrt{x^2+y^2}=1

As second condition we have that:

v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0

v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0

Which is the same:

y_1=-3x_1\\y_2=-3x_2

Replacing the second condition on the first condition we have:

\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}

Since x_1^2= \frac{1}{10} we have two posible solutions, x_1=\frac{1}{10} or x_1=-\frac{1}{10}. If we choose x_1=\frac{1}{10}, we can choose next the other solution for x_2.

Remembering,

y_1=-3x_1\\y_2=-3x_2

The two vectors we are looking for are:

v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})

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3 years ago
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crimeas [40]

Answer:

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