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Step2247 [10]
3 years ago
15

What is the slope of line segment AB? A) 2/3 B) 3/4 C) 4/3 D) -3/4

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0

Answer:

D) \displaystyle -\frac{3}{4}

Step-by-step explanation:

<em>B</em>[3, −3] and <em>A</em>[−5, 3]

\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-3 - 3}{5 + 3} = -\frac{6}{8} = -\frac{3}{4}

I am joyous to assist you anytime.

Lunna [17]3 years ago
3 0

For this case we have that by definition, the slope of a line is given by:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Where:

(x_ {1}, y_ {1})and (x_ {2}, y_ {2})are two points through which the line passes.

According to the image we have:

(x_ {1}, y_ {1}): (-5,3)\\(x_ {2}, y_ {2}): (3, -3)

Substituting we have:

m = \frac {-3-3} {3 - (- 5)} = \frac {-6} {3 + 5} = \frac {-6} {8} = - \frac {3} {4}

Thus, the slope of the line is:

m = - \frac {3} {4}

Answer:

m = - \frac {3} {4}

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1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Can anyone please help me with this?
Blizzard [7]

Answer:

8

Step-by-step explanation:

2/3·12=24/3=8

4 0
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