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dimulka [17.4K]
3 years ago
10

If a fish swims 7/8 of the depth of 32 foot deep lake, how many feet down did the fish swim?

Mathematics
1 answer:
erastova [34]3 years ago
4 0
The answer is 8÷32 4 4×7 28
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Solve the system using substitution. Show all work.
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Here is the answer I hope it helps

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What ratio is equivalent to 4:5 A. 10/15 B. 4/10 C. 16/20 D. 15/8
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Consider the following figure:
trasher [3.6K]

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C(cone with a radius of 8 units)

Explanation:

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If A and B are two angles in standard position in Quadrant I, find cos( A + B) for the given function values.
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2 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

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3 years ago
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