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andreev551 [17]

2 years ago

11

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

emist studying this reaction fills a 500. mL flask with 3.3 atm of sulfur dioxide gas and 0.79 atm of oxygen gas at 31.0 °C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 0.47 atm Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

0.051

Explanation:

Let's consider the following reaction.

2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)

We can compute the pressures using an ICE chart.

2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)

I 3.3 0.79 0

C -2x -x +2x

E 3.3-2x 0.79-x 2x

The partial pressure of sulfur trioxide gas is 0.47 atm. Then,

2x = 0.47

x = 0.24

The pressures at equilibrium are:

pSO₂ = 3.3-2x = 3.3-2(0.24) = 2.82 atm

pO₂ = 0.79-x = 0.79-0.24 = 0.55 atm

pSO₃ = 0.47 atm

The pressure equilibrium constant (Kp) is:

Kp = pSO₃² / pSO₂² × pO₂

Kp = 0.47² / 2.82² × 0.55

Kp = 0.051

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bagirrra123 [75]

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as $Na^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$ .

(2) Sodium is carrying +1 charge called as $Na^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_3PO_4$ .

(3) Sodium is carrying +1 charge called as $Na^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2SO_4$ .

(4) Sodium is carrying +1 charge called as $Na^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2CO_3$ .

(5) Potassium is carrying +1 charge called as $K^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $KCl$ .

(6) Potassium is carrying +1 charge called as $K^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $K_3PO_4$ .

(7) Potassium is carrying +1 charge called as $K^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $K_2SO_4$ .

(8) Potassium is carrying +1 charge called as $K^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $K_2CO_3$ .

(9) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $CaCl_2$ .

(10) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $Ca_3(PO_4)_2$ .

(11) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $CaSO_4$ .

(12) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $CaCO_3$ .

(13) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $NH_4Cl$ .

(14) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $NH_4_3PO_4$ .

(15) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $NH_4_2SO_4$ .

(16) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $NH_4_2CO_3$ .

(17) Iron is carrying +3 charge called as $Fe^{+3}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $FeCl_3$ .

(18) Iron is carrying +3 charge called as $Fe^{+3}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $FePO_4$ .

(19) Iron is carrying +3 charge called as $Fe^{+3}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $Fe_2(SO_4)_3$ .

(20) Iron is carrying +3 charge called as $Fe^{+3}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $Fe_2(CO_3)_3$ .

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2 years ago

Differentiate between sandy soil, clayey soil and loamy soil on the basis of the growth of plants????

ra1l [238]

The mixture of rock particle sand humus is called the soil.
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8 0

2 years ago

How many grams are in 3.8 moles of Li?

Sunny_sXe [5.5K]

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How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?

timama [110]

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

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3 0

2 years ago

Which of the following statements best compares the pH value of H3PO4 and HCl?

wel

Answer:

Option B. Both have a pH less than 7, but H3PO4 has a lower pH than HCl

Explanation:

Those are acid, so the pH would be < 7.

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HCl is a strong acid.

pH depends on [H]⁺

H₃PO₄ → 3H⁺ + PO₄⁻³

HCl → H⁺ + Cl⁻

If both acid, have the same concentration, [H⁺]H₃PO₄ > [H⁺]HCl, that's why the pH from the phosphoric will be lower.

5 0

3 years ago