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Answer:
Let the mixture is X% by mass of CuSO
4
.5H
2
O and 100 - X % by mass of MgSO
4
.7H
2
O. 5.0 g of mixture will contain 0.05X g CuSO
4
.5H
2
O and 5.0 - 0.05X g MgSO
4
.7H
2
O
The molar masses of CuSO
4
.5H
2
O and MgSO
4
.7H
2
O are 249.7 g/mol and 246.5 g/mol respectively.
The number of moles of CuSO
4
.5H
2
O=
249.7
0.05X
=2.00×10
−4
X moles.
Explanation:
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4(NH₄)₃PO₄ + 3Pb(NO₃)₄ → Pb₃(PO₄)₄ + 12NH₄NO₃
Explanation:
(NH₄)₃PO₄ + Pb(NO₃)₄ → Pb₃(PO₄)₄ + NH₄NO₃
Balancing this equation;
We simply use a mathematical approach by solving simple algebraic equations.
a(NH₄)₃PO₄ + bPb(NO₃)₄ → cPb₃(PO₄)₄ + dNH₄NO₃
a,b,c and d are the coefficients that will balance the equation;
Conserving N: 3a + 4b = 2d equation 1
H: 12a = 4d
P; a = 4c
O; 4a + 12b = 16c + 3d
Let us make a = 1;
c = 
d = 3
solving for b;
from (i); 4b = 2d -3a = 2(3) - 3(1) = 3
b = \frac{3}{4}
Now multiply a, b, c and d by 4;
a = 4 , b = 3 , c= 1 and d = 12
4(NH₄)₃PO₄ + 3Pb(NO₃)₄ → Pb₃(PO₄)₄ + 12NH₄NO₃
Learn more:
Balanced equation brainly.com/question/11102790
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-log(9)= -0.954
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