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Softa [21]
3 years ago
8

How will the candle contributes to the pressure and temperature of gases inside the glass?

Chemistry
1 answer:
Tems11 [23]3 years ago
7 0
How will the candle contributes to the pressure and temperature of gases inside the glass?

The candle contributes to the pressure and temperature of the gases inside the glass because of the increasing temperature the lit of the candle disposes into the gas molecules inside and as these gas molecules rise in temperature they become unsettling and since heat makes gas molecules robust the area becomes smaller for them to be ecstatic and as the dynamics is explained p=f/a the pressure increases.

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The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor p
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Answer : The vapor pressure of bromine at 10.0^oC is 0.1448 atm.

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The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

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P_1 = vapor pressure of bromine at 10.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 10.0^oC=273+10.0=283.0K

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Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{30910J/mole}{8.314J/K.mole}\times (\frac{1}{283.0K}-\frac{1}{331.8K})

P_1=0.1448atm

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3 years ago
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