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qwelly [4]
2 years ago
7

Plz answer me will mark as brainliest ​

Mathematics
1 answer:
nekit [7.7K]2 years ago
3 0

Answer:

c.1,2.3.5.7.11.13.17.19.23.29.31.37.41.43.47.53.59.61.67.71.73.79.83.89.97

d.no for example 9

e.no for example 2

f. 7,1,3,9

Step-by-step explanation:

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Can someone please help? I will mark brainlist!!!!
elena55 [62]

Answer:

D

Step-by-step explanation:

Because it moves 6 down and 6 right

4 0
2 years ago
Subtract one-third from 8 times b
steposvetlana [31]

i think the answer is 1/3 from 8x 6 =-46.7 i think

6 0
3 years ago
the sum of two numbers is 9. if one number is subtracted from the other, the result is 3. find the numbers
irakobra [83]
X, y - the numbers

The sum of the two numbers is 9.
x+y=9

If one number is subtracted from the other, the result is 3.
x-y=3

Solve the system of equations:
x+y=9 \\
\underline{x-y=3} \\
x+x=9+3 \\
2x=12 \ \ \ |\div 2 \\
x=6 \\ \\
x+y=9 \\
6+y=9 \ \ \ |-6 \\
y=3

The numbers are 6 and 3.
6 0
2 years ago
Read 2 more answers
Kylie starts with $145 in her piggy bank. Each month she adds $20.
djverab [1.8K]

Kylie's first month collection, a1= $ 145

Second month collection , a2= $145+ 20

Third month collection, a3  = $145 +2*20

.

.

.

.

so for n months collection = an-1+20

We get an= 20 + an-1  and a1=145


4 0
3 years ago
18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same princ
alexandr402 [8]

Explanation:

<em>Your premise and conclusion are both incorrect</em>.

120 has the prime factorization ...

  120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

__

1200 has the same prime factor and two more: 2·5, so the factorization is ...

  1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

__

When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

__

<em>Summary</em>

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

_____

<em>For reference</em>

Here are the divisors of 120:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200

7 0
3 years ago
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