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3 years ago

Solve for x: 3x/2 - 10 = 2

2 answers:

8 0

Move negative ten to the other side as a positive number

3x/2=12

Move two to the other side and multiply it by twelve

3x=24

Divide both sides by three

24/3 which is eight

Answer is eight

Roman55 [17]3 years ago

4 0

Answer:

2(2-10)/3=x

Step-by-step explanation:

2(2-10)=3x

2(2-10)/3=x

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Simplify this expression 5(6x)

nirvana33 [79]

30x! That was simple! Steps are shown below in case you need them!

5(6x)

(Now, you multiply 5*6)

30x

Bam!

$30x$

30x is da answer.

Hope that helps! Be sure to let me know if it does not!

8 0

4 years ago

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Which number must be added to 17,362 to result in a sum of 26,489? *

Kipish [7]

Answer: 9,127

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3 years ago

J squares a number and then find the square root of the result she needs to find up with 25 what number did Jay start with

Serggg [28]

Let

x -----> the number

we know that

The algebraic expression of the problem is giving by

x^2 -----> square a number

then

square root of the result

$\sqrt{x^2}=x$

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The final result is the same original number

7 0

1 year ago

What is the surface area of a cube of ice that is 64,000 cubic inches as the volume?

Lostsunrise [7]

I’m so sorry but I don’t have a clue! But you’ll get it eventually

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4 years ago

Question 5: prove that it’s =0

mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that $\cos(\frac{2}{x})$ is a variable number between -1 and 1 (inclusive).

This means that $-1 \le \cos(\frac{2}{x}) \le 1$ .

$x^4 \ge 0$ for all value $x$ . So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

$-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

By squeeze theorem, if $-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

and $\lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L$ , then we can also conclude that $\im_{x \rightarrow} x^4\cos(\frac{2}{x})=L$ .

So we can actually evaluate the "if" limits pretty easily since both are continuous and exist at $x=0$ .

$\lim_{x \rightarrow 0}x^4=0^4=0$

$\lim_{x \rightarrow 0}-x^4=-0^4=-0=0$ .

We can finally conclude that $\lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0$ by squeeze theorem.

Some people call this sandwich theorem.

6 0

3 years ago