All categories

4 years ago

I need to know how to write this as a decimal with all the steps and everything plzz

Mathematics

1 answer:

Crank4 years ago

4 0

You divide the denominator into the numerator and that will get your answer which is 7.

You might be interested in

11. The diagram below shows the radius of the circular opening of a bowl.

Ann [662]

Answer:

circumference=2πr=2×π×12.5=78.5cmis your answer

5 0

3 years ago

What is the area of this figure?

VikaD [51]

Answer:7

Step-by-step explanation:

3 0

3 years ago

Samantha works at a nursery where she pots plants. It takes her 1 1/2 hours to pot 12 plants. How many plants can Samantha pot i

ahrayia [7]

She can plot 9 in 1 hour

3 0

3 years ago

Select the values for a, b, and c that will make the following equation true.

vodomira [7]

Step-by-step explanation:

(x + 8)(x - 1) = x^2 - x + 8x - 8 = x^2 + 7x - 8.

Hence a = 1, b = 7, c = -8. (Options A, D and E)

4 0

4 years ago

Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.

svlad2 [7]

Answer:

$(x-2)^2+y^2=20$

Step-by-step explanation:

We want to find the equation of a circle P, and we know that the square RSTU is inscribed in the circle, this means that if we replace the points:

R(0,4) S(6,2) T(4,-4) and U(-2,-2) the equation must be verified.

Then, we have to replace the points in each option to see which one is the correct answer.

Option A: $(x-2)^2+y^2=68$

R(0,4):

$(x-2)^2+y^2=68\\(0-2)^2+4^2=68\\(-2)^2+16=68\\4+16=68\\20\neq 68$

We can see that R doesn't belong to the equation of the circle.

We could replace the rest of the points in the equation, but since we already know that R does not belong to the circle, we already know that it is not the right option.

Option B: $(x+2)^2+y^2=20$

R(0,4):

$(x+2)^2+y^2=20\\(0+2)^2+4^2=20\\2^2+4^2=20\\4+16=20\\20=20$

The point R(0,4) verifies the equation.

S(6,2):

$(x+2)^2+y^2=20\\(6+2)^2+2^2=20\\8^2+4^2=20\\64+16=20\\80\neq 20$

The point S doesn't belong to the equation of the circle, then we already know that this isn't the correct option.

Option C: $(x-2)^2+y^2=20$

R(0,4):

$(x-2)^2+y^2=20\\(0-2)^2+4^2=20\\(-2)^2+16=20\\4+16=20\\20=20$

The point R verifies the equation.

S(6,2):

$(x-2)^2+y^2=20\\(6-2)^2+2^2=20\\4^2+4=20\\16+4=20\\20=20$

The point S verifies the equation.

T(4,-4):

$(x-2)^2+y^2=20\\(4-2)^2+(-4)^2=20\\2^2+16=20\\4+16=20\\20=20$

The point T verifies the equation.

U(-2,-2):

$(x-2)^2+y^2=20\\(-2-2)^2+(-2)^2=20\\(-4)^2+4=20\\16+4=20\\20=20$

The point U verifies the equation.

<em>We can see that the four points RSTU verifies the equation. This means that the square RSTU is inscribed in circle P whose equation is: </em> $(x-2)^2+y^2=20$

<em>We can see that the graph of the equation verifies the answer.</em>

3 0

4 years ago