Answer:
6sqrt2(cos(-5pie/4)+isin(-5pie/5))
Step-by-step explanation:
Okay so she had 67 homework problems and she only finished 25
she has 7 pages to complete and on each page the same number of problems
So we can use subtraction and division
(67 - 25) : 7 =
42 : 7 =
6
So there are 6 problems on each page :)
The unknown angles in the cyclic quadrilateral is as follows:
∠BGX = 74° (sum of angles in a triangle)
∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 100°(sum of angles in a triangle)
∠BCG = 26°
∠BFG = 22°
<h3>Cyclic Quadrilateral</h3>
A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.
Let's find the missing angles as follows:
∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)
∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)
∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)
∠BCG = 100 - 74 = 26°
∠BFG ≅ CBF = 22°(alternate angles)
learn more on angles here: brainly.com/question/19430381
I believe it’s 5, 2 you would just you 2,-2 as a line segment
Set up the equation so m<HCB + m<DCH = m<DCB
2x + 100 + 60 = x + 170
2x+ 160 = x +170
-x -x
x + 160 = 170
- 160 -160
x = 10