Which value is the solution of the equation 5y-4x=-3

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

Tiana can clear a football field of debris in 3 hours. Jacob can clear the same field in 2 hours. If they decide to clear the fi

Marianna [84]

You must find the relative rates of both workers...

T=f/3 and J=f/2 so if they work together to clear the field then:

ft/3+ft/2=f make all terms have a common denominator of 6

(2/2)(ft/3)+(3/3)(ft/2)=(6/6)f

2ft/6+3ft/6=6f/6 multiply both sides by 6

2ft+3ft=6f divide both sides by f

2t+3t=6 combine like terms on left side

5t=6 divide both sides by 5

t=6/5 hr

t=1 1/5 hr

t=1 hr 12 min

8 0

3 years ago

Solve. x2 + 14 = 9x A) x = 2, x = 7 B) x = 3, x = 5 C) x = −2, x = −7 D) x = −3, x = −5

chubhunter [2.5K]

Answer:

A) x = 2, x = 7

Step-by-step explanation:

x^2 + 14 = 9x

Subtract 9x from each side

x^2-9x + 14 = 9x-9x

x^2-9x + 14 = 0

What 2 numbers multiply to 14 and add to -9

-7*-2 = 14

-7+-2 = -9

(x-7)(x-2) = 0

Using the zero product property

x-7 = 0 x-2 =0

x=7 x=2

7 0

3 years ago

Just need a step-by-step on how to do it

blsea [12.9K]

Answer:

area of the shape is 12,6 5 2

3 0

1 year ago

A door frame is 7 feet high. In order to accommodate a larger door, the frame

Artemon [7]

First you need to get 3% of 7 so
7x0.03= 0.21
then you need to add that 3% onto 7
7+0.21=7.21
therefore the door frame is now 7.21 feet high

7 0

3 years ago