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Nimfa-mama [501]

3 years ago

13

Which value is the solution of the equation 5y-4x=-3

1 answer:

Lelechka [254]3 years ago

7 0

I hope this helps you

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Find the general solution of the given differential equations. Give the largest interval I over which the general solution is de

e-lub [12.9K]

The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)

The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
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The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>

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2 years ago

What is the number when 0.83 is written as a fraction with a denominator of 100?

Grace [21]

The fraction would be 83/100

7 0

3 years ago

Read 2 more answers

How to simplify the equation above?

Mama L [17]

if you need more help, always ask. It wasn't simple, but I believe you can do it.

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3 years ago

Please help me quickly! During spring, every three days there is usually 1 rainy day. In a 30 day month, how many days would you

OleMash [197]

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1. 10 rainy days

2. 24 points

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7 0

2 years ago

Solve for x in the equation x² + 14x + 17 = - 96

gavmur [86]

Answer:

Solutions of x are;

x = -7 + 8i and x = -7 -8i

Step-by-step explanation:

Given the equation: $x^2+14x+17 = -96$

Add 96 both sides we get;

$x^2+14x+17+96 = 0$

$x^2+14x+113= 0$

Using quadratic formula $ax^2+bx+c = 0$ then the solution is given by:

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing we have;

a= 1, b =14 and c =113

$x = \frac{-14\pm\sqrt{(14)^2-4(1)(113)}}{2(1)}$

$x = \frac{-14\pm\sqrt{196-452}}{2}$

or

$x = \frac{-14\pm\sqrt{-256}}{2}$

Simplify:

$x = \frac{-14\pm 16i}{2}$ ; where i is the imaginary, $i^2= -1$

or

$x = -7 \pm 8i$

Therefore, the solution of x are; x = -7 + 8i and x = -7 -8i

4 0

2 years ago