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Nata [24]
4 years ago
15

Which best explains why metal cooking utensils often have plastic coating on their handles?

Physics
1 answer:
beks73 [17]4 years ago
7 0
Metal cooking utensils often have plastic coating on their handles because if you touch a bare metal handle you would get burned.
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In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce
worty [1.4K]

Answer:

b. 0.75 mm

Explanation:

The distance between antinodes d is half the wavelength \lambda. We can obtain the wavelength with the formula v=\lambda f, where f is the frequency given (f=1MHz=1\times10^6Hz) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:

d=\frac{\lambda}{2}=\frac{v}{2f}=\frac{1540m/s}{2(1\times10^6Hz)}=0.00077m=0.77mm

which is very close to the 0.75mm option.

4 0
4 years ago
X + 10 times X = 50 what is the answer
tia_tia [17]

Answer:

4.54

Explanation:

X+10X=50

11X=50

X=4.54#

<h2>please follow me...</h2>
3 0
3 years ago
A car is traveling with a constant speed of 30.0 m/s when the driver suddenly applies the brakes, causing the car to slow down w
Black_prince [1.1K]

Answer:

a = - 3.75 m/s²

negative sign indicates deceleration here.

Explanation:

In order to find the constant deceleration of the car, as it stops, we will use the 3rd equation of motion. The 3rd equation of motion is as follows:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration of the car = ?

Vf = Final Velocity = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity = 30 m/s

s = distance covered by the car = 120 m

Therefore,

a = [(0 m/s)² - (30 m/s)²]/(2)(120 m)

<u>a = - 3.75 m/s²</u>

<u>negative sign indicates deceleration here.</u>

7 0
3 years ago
A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
What is the speed of sound dependent on?
mojhsa [17]
Depends on the elasticity and density of the medium through what it is traveling <span> </span>
5 0
3 years ago
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