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Nata [24]
4 years ago
15

Which best explains why metal cooking utensils often have plastic coating on their handles?

Physics
1 answer:
beks73 [17]4 years ago
7 0
Metal cooking utensils often have plastic coating on their handles because if you touch a bare metal handle you would get burned.
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Limestone is an example of
inessss [21]
A. A clastic Sedimentary rock
7 0
3 years ago
Two objects with masses of 2.75 kg and 4.45 kg are connected by a light string that passes over a light frictionless pulley to f
Llana [10]

Answer:

Explanation:

F = ma

4.45g - 2.75g = (4.45 + 2.75)a

a = 9.81(4.45 - 2.75) / (4.45 + 2.75) = 2.31625 ≈ 2.32 m/s²

a)

T = 2.75(9.81 + 2.32) = 33.3 N

or

T = 4.45(9.81 - 2.32) = 33.3 N

b) 2.32 m/s² upward for 2.75 kg mass

    2.32 m/s² downward for 4.45 kg mass

c) y = ½at² = ½(2.31625/3)1² = 1.158125 ≈ 1.16 m

4 0
3 years ago
Net force is the sum of all forces acting on an object. For example, in a tug of war, when one team is pulling the rope with a f
melisa1 [442]

Answer:

If there are equal forces in both directions and there is no motion, the net force is 0 Newtons. This is because you'd be subtracting 100 from 100 which just equals 0.

5 0
3 years ago
A 1000 kg elevator is rising and its speed is increasing with an acceleration of 3 m/s^2. What is the resulting tension in the v
Alchen [17]

Answer:

12800 N

Explanation:

7 0
3 years ago
Tests reveal that a normal driver takes about 0.75 s before he or she can react to a situation to avoid a collision. It takes ab
nata0808 [166]

To solve this problem we will apply the linear motion kinematic equations. On these equations we will define the speed as the distance traveled in a space of time, and that speed will be in charge of indicating the reaction rate of the individual. In turn, using the ratio of speed, position and acceleration, we will clear the position and determine the distance necessary for braking.

The relation to express the velocity in terms of position for constant acceleration is as follows

v^2 = u^2+2a(s-s_0)

Here,

u = Initial velocity

v= Final velocity

a = Acceleration

s_0 = Initial position

s = Final position

PART 1) Calculate the displacement within the reaction time

d = vt

d = (44)(0.75)

d = 33ft

In this case we can calculate the shortest stopping distance

0^2 = 44^2+2(-2)(s-33)

s = 517ft

PART 2)

PART 1) Calculate the displacement within the reaction time

d = vt

d = (44)(3)

d = 132ft

In this case we can calculate the shortest stopping distance

0^2 = 44^2+2(-2)(s-132)

s = 616ft

While a person without alcohol would cost 517ft to slow down, under alcoholic substances that distance would be 616ft

7 0
4 years ago
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