From the geometry of the problem, the 20 m-long cable creates
the hypotenuse of a right triangle, with the extended of the other two sides of
size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased
by 20 m - 17.3 m = 2.7 m.
The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 *
1.6 m , or about 37044 joules.
Given :
You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.
To Find :
What is the ball velocity at the higher point that the ball reaches.
Solution :
We know, when ball is moving upward acceleration due to gravity is applied downward.
So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.
Therefore, ball velocity is 0 m/s at maximum height.
Hence, this is the required solution.
If the object being represented is going both up and to the right.
Given:
Initial speed of the motorcycle (u) = 35 m/s
Final speed of the motorcycle (v) = 0 m/s (Complete Stop)
Maximum deceleration of the motorcycle (a) = -1.2 m/s²
Required Equation:
Answer:
By substituting values in the equation, we get:
Time taken by motorcycle to come to a complete stop (t) = 29.167 s
