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vlada-n [284]
3 years ago
13

Which number goes on the x-axis ( 4,6) ?​

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer:

the answer is 4

Step-by-step explanation:

You only have to know what is first x or y

Sedbober [7]3 years ago
5 0

Answer: 4 is on the x axis because if you graph the point you will run then jump on the coordinate plane and 4 will be on the x axis.

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Parallelogram TUVW is graphed on a coordinate plane with vertices at T (3, 4), V (-10,-2), V(-6,5),
zalisa [80]

The coordinates of the dilated vertex V' is (-6p, 5p)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, reflection, rotation and dilation.</em>

<em />

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

The Parallelogram TUVW has vertices at T(3, 4), U(-10,-2), V(-6,5) and  W (7,11). If it is dilated by a scale factor p with the origin, the new point is at:

T'(3p, 4p), U'(-10p, -2p), V'(-6p, 5p) and W'(7p, 11p)

Find out more on dilation at:brainly.com/question/10253650

3 0
2 years ago
When is a zero not significant?
fomenos

Answer: A. When it comes after the decimal point, as in 4.000

Step-by-step explanation: If there are no other numbers after the zeros, there is no reason for them to be place holders. Zeros in decimals act as place holders such as in 4.09 or 4.0009. This actually does change the value of the decimal but 4.000 is just the same as a regular old 4. Hope this helps!

7 0
3 years ago
Read 2 more answers
I got disconnected from my tutor, can't reconnect. need an explanation ​
kherson [118]

The absolute value function |<em>x</em>| always returns a non-negative number. It takes any number <em>x</em> and returns <em>x</em> if it's already non-negative, or -<em>x</em> if it is negative in order to make it positive.

|x|=\begin{cases}x&\text{for }x\ge0\\-x&\text{for }x

For the equation

-3 + 4 |2<em>x</em> - 5| = 14

rearrange terms to get

|2<em>x</em> - 5| = 17/4

Now,

• if 2<em>x</em> - 5 ≥ 0, then |2<em>x</em> - 5| = 2<em>x</em> - 5. Then

2<em>x</em> - 5 = 17/4

• and if instead 2<em>x</em> - 5 < 0, then |2<em>x</em> - 5| = -(2<em>x</em> - 5), so that

-(2<em>x</em> - 5) = 17/4, or

2<em>x</em> - 5 = -17/4

In the first case,

2<em>x</em> - 5 = 17/4

2<em>x</em> = 17/4 + 5 = 37/4

<em>x</em> = 37/8

In the second case,

2<em>x</em> - 5 = -17/4

2<em>x</em> = -17/4 + 5 = 3/4

<em>x</em> = 3/8

5 0
3 years ago
Could you explain to me how to do this ? I do not understand at all
alexandr1967 [171]

Answer:

I believe this is how you do it

Step-by-step explanation:

csc∅tan∅

(1/sin∅)(sin∅/cos∅)

(sin∅)/(sin∅cos∅)

1/(cos∅)

sec∅

csc²∅tan²∅sin∅

1/(sin²∅) * tan²∅ * sin∅

tan²∅/sin²∅ * sin∅

tan²∅/sin∅

5 0
3 years ago
Find the equation of the line given the slope and the y-intercept
GREYUIT [131]

Answer:

y = \frac{1}{2}x + 3

Step-by-step explanation:

The equation for a linear graph is usually written in the following format...

y = mx + b

Where m would be the slope, usually referring to rise over run and b would be the y-intercept (where the line crosses the y-axis). From the graph, we can see that the line crosses the y-axis at point 3 so b would be 3. The graph also shows us that for every 1 value that the line rises it moves to the right 2 values. Therefore, the slope would be 1/2. Using these values we can create the following equation...

y = \frac{1}{2}x + 3

7 0
3 years ago
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