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3 years ago

Which number goes on the x-axis ( 4,6) ?

Mathematics

2 answers:

fenix001 [56]3 years ago

8 0

Answer:

the answer is 4

Step-by-step explanation:

You only have to know what is first x or y

Sedbober [7]3 years ago

5 0

Answer: 4 is on the x axis because if you graph the point you will run then jump on the coordinate plane and 4 will be on the x axis.

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Dividir 254 en tres partes tales que la segundasea el triplo de la primera y 40 unidades mayor que la tercera

Gelneren [198K]

Responder:

x = 40

y = 120

z = 80

Explicación paso a paso:

Número dividido = 240

Las 3 partes:

x, y, z

y = 3x

Z = 3x - 40

x + y + z = 240

x + 3x + 3x - 40 = 240

7x - 40 = 240

7x = 240 + 40

7x = 280

x = 280/7

x = 40

y = 3 (40)

y = 120

z = 3x - 40

z = 3 (40) - 40

z = 120 - 40

z = 80

5 0

3 years ago

I’m in need of help on this please

STALIN [3.7K]

Answer:

Im going to use the Pythagorean theorem.

a^2+b^2=c^2

Line AB is A, line CB is B, and line AC is C.

4^2+2^2=c^2

4^2=16 and 2^2=4

16+4=20^2=4.5

4.5 shoudl be your answer.

-Seth

4 0

3 years ago

Read 2 more answers

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

4 years ago

Simplify<br> i need help simplifying this

abruzzese [7]

Answer:

1/4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How do i divide 806 by 9 with long division, im getting 9 remainder 6

d1i1m1o1n [39]

9/806 = 9 goes into 80 8 times which gives you 72. 80-72 is 8 and when you bring down the 6, 9 goes into 86 9 times with a remainder of 5 . This gives you 89 R 5

8 0

3 years ago

Which number goes on the x-axis ( 4,6) ?​

Which number goes on the x-axis ( 4,6) ?