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4 years ago

15

The vertices of a polygon are L(3,4), M (3,6), N (9,6), O (9,4), P(7,0), and Q(5,0). Graph the polygon. Then

1 answer:

mixas84 [53]4 years ago

6 0

Answer:

28 is the area

Step-by-step explanation:

when graphed, the polygon should look like this,

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What is the the frequency of the sinusoidal graph ??

ira [324]

For e2020 the answer is C

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3 years ago

How many times longer is the diameter of a grain of sand than the diameter of the average cell in the human body? Show your work

kolezko [41]

100 times longer because the sand grand is a very tiny particle

7 0

3 years ago

Given the following a=3,b=4, what is the length of side c?<br> 5<br> 6<br> 4

e-lub [12.9K]

Answer:

C=5

Step-by-step explanation:

3^ + 4^2 = 25

and the square root of 25 is 5 therefore C=5

6 0

4 years ago

The table represents the observed number of leaves y on x branches of a tree. Calculate the rate of change between 3 and 4 branc

Dennis_Churaev [7]

Answer:

<h2>25</h2>

Step-by-step explanation:

The rate of change of number of tree y on x branches of a tree is expressed as shown;

m = Δy/Δx where;

m is the rate of change

Δy is the change in number of leaves between 3 and 4

Δx is change in number of branches between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

From table between 3 and 4, y₂ = 100, y₁ = 75, x₂ = 4, x₁ = 3

m = 100-75/4-3

m = 25/1

m = 25

<em>Hence the rate of change between 3 and 4 branches is 25</em>

5 0

3 years ago

Write anwsers as fractions using / as fraction bar and write the greater value first

puteri [66]

Answer:

Final answer is $\frac{3}{2}$ or $\frac{1}{2}$ .

Step-by-step explanation:

Given equation is $\log_x\left(8x-3\right)-\log_x\left(4\right)=2$

Now we need to solve that equation for x.

$\log_x\left(8x-3\right)-\log_x\left(4\right)=2$

Apply formula $\log_c\left(A\right)-\log_c\left(B\right)=\log_c\left(\frac{A}{B}\right)$

$\log_x\left(\frac{8x-3}{4}\right)=2$

Apply formula $\log_c\left(A\right)=b \Rightarrow c^b=A$

$x^2=\frac{8x-3}{4}$

$4x^2=8x-3$

$4x^2-8x+3=0$

$4x^2-2x-6x+3=0$

$2x(2x-1)-3(2x-1)=0$

$(2x-3)(2x-1)=0$

$2x-3=0$ or $2x-1=0$

$2x=3$ or $2x=1$

$x=\frac{3}{2}$ or $x=\frac{1}{2}$

Hence final answer is $\frac{3}{2}$ or $\frac{1}{2}$ .

6 0

4 years ago