Can someone please HELP!
1 answer:
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Complete Question: In Rhombus QRST, diagonals RT and QS are drawn. If m<TSR = 104°, then which of the following is the measure of <SRT?
*the diagram of the rhombus is in the attachment below
Answer:
m<SRT = 38°
Step-by-step explanation:
A rhombus has 4 equal sides. Also, diagonals of a rhombus bisect each other Therefore:
∆RST form the rhombus given is an isosceles triangle with two equal lengths, ST and SR, and two equal base angles, <T and <R.
Given that <TSR = 104°, thus,
m<SRT = (180 - 104)/2 = 76/2
m<SRT = 38°
Answer:
p > 10.67
Step-by-step explanation:
Given the inequality -1 1/2p < -16
Before we can represent the inequality on a graph we just simplify it first. On simplification:
-1 1/2p < -16
(-3/2)p < -16
Multiplying both sides by 2
-3p < -32
Dividing both sides by -3 will change the sense of the inequality as shown:
p > -32/-3
p > 32/3
p > 10.67
Find the graph of the resulting inequality in the attachment.
