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s2008m [1.1K]
3 years ago
8

Write the equation of the perpendicular bisector of . Point B is located at (–3, 1), and point C is located at (1, 5).

Mathematics
1 answer:
maxonik [38]3 years ago
6 0

The equation of perpendicular bisector of BC is

y=-x+2

Further explanation:

A perpendicular bisector passes through the mid-point of a line so to get an ordered pair from which the perpendicular bisector will pass we need to find the mid-point of BC.

Mid-point = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )\\Here\\(x_1,y_1) = (-3,1)\\(x_2,y_2) = (1,5)\\Putting\ values\ in\ formula\\M = (\frac{-3+1}{2} , \frac{1+5}{2} )\\= (\frac{-2}{2} ,\frac{6}{2})\\= (-1, 3)

So the perpendicular bisector will pass through (-1,3)

Let m1 be the slope of BC

Then

m_1 = \frac{y_2-y_1}{x_2-x_1} \\=\frac{5-1}{1+3} \\=\frac{4}{4}\\ =1

Let m2 be the slope of perpendicular bisector

We know that the product of slopes of perpendicular lines is -1.

m_1.m_2 = -1\\1*m_2 = -1\\m_2 = -1

The standard form of point-slope form of line is:

y=mx+b

Putting the value of slope of bisector we get

y=(-1)(x)+b\\y=-x+b

To find the value of b, put the ordered pair (-1,3) in the equation

3 = -(-1) +b\\3= 1+b\\3-1 =b\\b=2\\

Putting the values of m and b in standard form

y=-x+2

Hence the equation of perpendicular bisector of BC is

y=-x+2

Keywords: Perpendicular bisector, Point-slope form

Learn more about point-slope form at:

  • brainly.com/question/7490805
  • brainly.com/question/8358304

#LearnwithBrainly

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Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

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Answer:

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Step-by-step explanation:

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Answer:

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y = | x | - 4

y = | -1 | - 4

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