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3 years ago

How do i graph x-y=-3

2 answers:

6 0

X - y = -3
y = x + 3.......slope = 1, y intercept = (0,3)

to find x int, sub in 0 for y and solve for x
x - y = -3
x - 0 = -3
x = -3....so the x intercept = (-3,0)

plot ur points (0,3) and (-3,0)......now start at (-3,0)....and since ur slope is 1, go up one, and to the right 1, and up 1, and to the right 1.....do this over as many times as needed and u should cross the y axis at (0,3)

mr_godi [17]3 years ago

6 0

Go where -3 on the y axis and the -3 on the x axis meet up and put a dot there.

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Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 $\neq$ 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 $\neq$ 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 $\neq$ 13

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3 0

3 years ago

Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.

Rufina [12.5K]

Answer: k = -1 +/- √769

Step-by-step explanation:

48x - ky = 11

-48x -48x

-ky = -48x + 11

$\frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}$

$y =\frac{48x}{k} - \frac{11}{k}$

Slope: $\frac{48}{k}$

*************************************************************************

(k + 2)x + 16y = -19

- (k + 2)x -(k + 2)x

16y = -(k + 2)x - 19

$\frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}$

$y = -\frac{(k + 2)x}{16} - \frac{19}{16}$

Slope: $-\frac{(k + 2)}{16}$

**********************************************************************************

$\frac{48}{k}$ and $-\frac{(k + 2)}{16}$ are perpendicular so they have opposite signs and are reciprocals of each other. When multiplied by its reciprocal, their product equals -1.

$-\frac{(k + 2)}{16}$ * $\frac{k}{48}$ = -1

$\frac{(k + 2)k}{16(48)}$ = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769

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3 years ago