Answer:
2.25 seconds
87 feet
[6, 87]
Step-by-step explanation:
The height of a projectile is:
h(t) = -16t² + vt + s
where v is the initial vertical velocity and s is the initial height.
Here, v = 72 and s = 6.
h(t) = -16t² + 72t + 6
This is a downwards parabola. The maximum is at the vertex.
t = -b / (2a)
t = -72 / (2×-16)
t = 2.25
h(2.25) = 87
It takes 2.25 seconds to reach the maximum height of 87 feet.
The range is from the lowest height (6 feet) to the maximum height (87 feet). In interval notation:
[6, 87]
Answer:
dont click that other guys link its an ip grabber
Step-by-step explanation:
-4y = 8x
y = 8x/-4
y = -2x
The constant of variation is -2
8:7...added = 15
(8/15(90) / 2= 48/2 = 24
(7/15(90) / 2 = 42/2 = 21
dimensions are : 24 ft by 21 ft
