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Blababa [14]
2 years ago
5

Select the correct answer.

Mathematics
1 answer:
aleksley [76]2 years ago
3 0

Answer:

$24,890.46, $25,109.59

Step-by-step explanation:

Given:

n = 48, the sample size

m = $25,000, th sample mean

σ = $3000, the maximum variance

The standard deviation is

s = √σ = √(3000) = 54.772

As a rule of thumb, the range is 4 times the standard deviation. Therefore the range is

R = 4*54.772 = 219.09

Half the range is

R/2 = 219.09/2 = 109.45

The required  range is

(25000-109.45, 25000+109.45) = (24890.46, 25109.54)

Answer: $24,890.46, $25,109.54

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The slope-intercept form can be obtained by solving for y.

8x-y=-6

-8x

-y=-8x-6

divide by negative 1 to turn y positive.

y=8x+6

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3 years ago
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a. around 36.36 hours; around 28.57 hours

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Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

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b= √10

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The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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-4 1/2, -5.6, -2 3/8, 2.35 from least to greatest
sweet-ann [11.9K]
Hello!

-2 3/8, -5.6, -4 1/2, 2.35.

Those are ordered from least to greatest!

I really hope you found this helpful! c:
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3 years ago
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