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ziro4ka [17]
2 years ago
7

Write the equation of the circle centered at (3, 5) and tangent to x = -1. I need help pleasse

Mathematics
1 answer:
Annette [7]2 years ago
7 0

Answer:

(x - 3)² + (y - 5)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given (h, k ) = (3, 5 ) we require to find r

r is the distance from the centre to a point on the circle

given x = - 1 is a tangent the r is the distance between the x- coordinates

r = | 3 - (- 1) | = | 3 + 1 | = | 4 | = 4

then equation of circle is

(x - 3)² + (y - 5)² = 4² , that is

(x - 3)² + (y - 5)² = 16

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a diameter is 2 × the radius
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I will solve the first question to show how to format.

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2 years ago
What is the graph for y<2x-5,y>-3x+1
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3 years ago
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<span>47184. 
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5 0
3 years ago
ABF = EDG. GCF are equilateral. AG = 21 and CG 1/4 Find the total distance from A to B to C to D to E.
hjlf

The information given in the triangle shows that the total distance from A to B to C to D to E will be C. 84.

<h3>How to calculate the triangle?</h3>

From the information given, ABF = EDG, GCF are equilateral and AG = 21 while CG = 1/4.

The total distance from A to B to C to D to E will be:

= 21/CG

= 21 / 1/4

= 21/0.25

= 84

In conclusion, the correct option is 84.

Learn more about triangles on:

brainly.com/question/17335144

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