The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.
Given two points of a line (1,5) and (-2,-4).
We have to form an equation in slop intercept form.
Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.
Point slope form of an equation is y=x+mc where m is slope of the line.
From two points the formula of equation is as under:
(y-
)=
*(x-
)
where
are the points.
Putting the values of
=1,
=-2,
=5 and
=-4.
y-5=(-4-5/-2-1)*(x-1)
y-5=-9/-3*(x-1)
y-5=3(x-1)
y-5=3x-3
y=3x-3+5
y=3x+2
Hence the slope intercept form of the line having points (1,5)(-2,-4) is y=3x+2.
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21x + 84 + 12x - 16
33x + 68
The correct answer is 1.) 33x + 68.
Hope this helps!
The answer is c or the third option. If we start at one we get (4(1)-9)=-5, then we can do 2 and we get (4(2)-9)=-1. Lets do 3 (4(3)-9)=3. Now 4 (4(4)-9)=7. Now 5 and our last one (4(5)-9)=11. Now notice we get -5+-1+3+7+11.