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Hoochie [10]
3 years ago
9

Factor each of the following. Remember: It is the reverse of the distributive property and your first step is to find the greate

st common factor of all terms.

Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0
To factor using the reverse of the distributive property, find what common factor the numbers have and what common factor the variables have.

10.

-8x - 16

8 is a factor of both -8 and 16.
The first term has x, but the second term does not, so there is no common variable. The only common factor is 8, or -8.

Factor out a -8:

-8x - 16 = -8(x + 2)

To see if the factorization is correct, multiply the answer using the distributive property. If you get the original expression, then the factorization is correct.

11.

w^2 - 4w

The first term only has a factor of 1. The second term has a 4. There is no common factor between 1 and 4 except for 1, so there is no number you can factor out. The first term has w^2. The second term has w. Both terms have a common factor of w. We can factor out w from both terms.

w^2 - 4w = w(w - 4)

12.

4s + 10rs

4 and 10 have a common factor of 2.
s and rs have a common factor of s.
2 times s is 2s, so the common factor is 2s.
We now factor out 2s

4s + 10rs = 2s(2 + 5r)
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If you have 8 slices of pis and gave away 3/4 how many are left
Maru [420]
8 - 3/4 = 4.6 let me know if I made any mistakes =^-^=
3 0
3 years ago
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Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that
ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

T: 1 \ R^n \to  1 \ R^n is invertible lines transformation

S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \  \varepsilon\ 1 R^n\\\\

T is invertiable linear transformation means that is  

T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix

and \ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists

Let

V \varepsilon\  a\  R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v

so,  

s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \  \forall \ \ v \ \ \varepsilon \ \ 1 R^n

7 0
3 years ago
In the Simple Interest Formula I=prt, what does the I stand for?
GREYUIT [131]

Answer:

I = interest

Step-by-step explanation:

I=prt

I = interest

p = principle

r = rate

t = time

7 0
3 years ago
Read 2 more answers
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
Solve the system using elimination.<br> 2x + 18y = -9<br> 4x + 18y = -27
Elan Coil [88]

First, let's cancel out the x by multiplying 2x + 18y = -9 by -2.

-2 ( 2x + 18y = -9) = -4x -36y = 18

Then, we combine the two equations.

-4x + 4x = 0

18y - 36y = -18y

-27 + 18 = -9

Our new equation is -18y = -9.

Now, divide both sides by -18.

-18y / -18 = y

-9/ -18 = 1/2

y = 1/2

We can plug in a value for y since y = 1/2 now.

Let's use 2x + 18y = -9

Plug in y.

2x + 18(1/2) = -9

2x + 9 = -9

Then, subtract 9 from both sides.

2x = -18

Divide by 2.

2x/2 = x

-18/2 = -9

x = -9

Lastly, we can plug in both x and y values to see it works.

2(-9) + 18(1/2) = -9

-18 + 9 = -9

Therefore, the values of x and y does work.

x = -9

y = 1/2

4 0
3 years ago
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