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faust18 [17]
3 years ago
7

One hundred students were surveyed and asked if they participate in band and if they play a sport. The table below summarizes th

eir responses.
Of students that do NOT play a sport, what is the relative frequency of those who participate in band?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

22/30

Step-by-step explanation:

22 students participate in band and 8 do not. The total number of students that don't play sports are 30 in total cause 22 + 8 = 30.

So, 22/30

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Laura is putting her dog on a diet.
Vera_Pavlovna [14]

Answer:

it would take 12 months

Step-by-step explanation:

is she currently weighs 110 pounds and u want her to get to 80 then we have to subtract 110-80 which equals 30 and since she loses 2.5 pounds per month then we have to divide 30/2.5 which makes 12 so now ur answer is 12MONTHS

6 0
3 years ago
I=$24, P=$400, t=2 years The annual interest rate is %.
kolbaska11 [484]

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8 0
4 years ago
If line t is a transversal of lines l and m, name the angle relationship of the given angle pairs.
Ghella [55]

Answer:

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and they are supplementary(sum=180°).

Step-by-step explanation:

Given:

Line l\parallel m

Line t is traversal.

By angle properties we can name the angle relationship of given angle pairs.

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and thus they are supplementary.

8 0
3 years ago
.
jarptica [38.1K]

Answer:

3 gallons

Step-by-step explanation:

Let

x ----> the amount of pure acid (100% solution) in gallons

Remember that

100\%=100/100=1

20\%=20/100=0.20

60\%=60/100=0.60

we know that

(1)(x)+(0.20)(3)=(0.60)(x+3)

solve for x

x+0.60=0.60x+1.80

x-0.60x=1.80-0.60\\0.40x=1.20\\x=3\ gal

therefore

3 gallons of pure acid should be mixed with 3 gallons of a 20% acid solution in  order to get a 60% acid solution

7 0
3 years ago
Last night, the two dinner specials at Henry's favorite restaurant were salmon filet and steak. The restaurant served 55 special
sergeinik [125]
Since 11 out of 55 specials were salmon filet,

The percentage of specials that were salmon filet is 11/55 = 20/100 = 20%.
7 0
3 years ago
Read 2 more answers
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