Answer:
952.2g SO3
Explanation:
Molar mass of C4H8S2 is 120.2363 g/mol
Mol in 750.0g = 750.0/120.2363 = 6.238 mol
1mol C4H8S2 produces 2 mol SO3
6.238 mol will produce 2×6.238 = 12.476 mol SO3
Molar mass SO3 = 32+3×16 = 80.0g/mol
Theoretical yield = 12.476×80.0 = 998.08g
The actual yield is 95.4%
Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced
Hope it will help you.
Answer: A
Explanation: moving through the cathode
Answer: The number of moles of
produced are, 0.287 moles.
Explanation : Given,
Mass of
= 14.9 g
Molar mass of
= 32 g/mol
First we have to calculate the moles of ![O_2](https://tex.z-dn.net/?f=O_2)
![\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DO_2%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%20%7DO_2%7D%7B%5Ctext%7BMolar%20mass%20%7DO_2%7D)
![\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DO_2%3D%5Cfrac%7B14.9g%7D%7B32g%2Fmol%7D%3D0.466mol)
Now we have to calculate the moles of ![CO_2](https://tex.z-dn.net/?f=CO_2)
The balanced chemical equation is:
![2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2](https://tex.z-dn.net/?f=2C_4H_%7B10%7D%2B13O_2%5Crightarrow%2010H_2O%2B8CO_2)
From the reaction, we conclude that
As, 13 mole of
react to give 8 moles of ![CO_2](https://tex.z-dn.net/?f=CO_2)
So, 0.466 mole of
react to give
mole of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Therefore, the number of moles of
produced are, 0.287 moles.
Answer:
The different objects that make up a circuit are called components. A circuit must have a power source, such as a battery, and the current flows through a conductor, such as a wire.
Explanation:
I hope that was useful.