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klio [65]
2 years ago
10

Which of the following would be classified as an acid to the Arrhenius definition

Chemistry
2 answers:
mixer [17]2 years ago
4 0

Any substance that increases the concentration of H^+ in aqueous solutions is Arrhenius's acid.

<h3>What are Arrhenius acids?</h3>

Arrhenius define acids as substances with the chemical capacities to increase the concentration of hydrogen ion in aqueous solutions.

Thus, substances like HCl, HNO3, HBr, etc. would be considered an acid. This is because they ionize in aqueous solutions as follows:

HCl ---> H^+ + Cl^-

HNO_3 --- > H^+ + NO_3^-

HBr --- > H^+ + Br^-

More on Arrhenius acids can be found here: brainly.com/question/9936252

#SPJ1

Luden [163]2 years ago
3 0

Hydrochloric acid would be classified as an acid to the Arrhenius definition due to giving of hydrogen ions.

<h3>How acid is defined according to the Arrhenius definition?</h3>

According to Arrhenius concept, hydrochloric acid is an acid which gives hydrogen ions in water while on the other hand, according to Bronsted-Lowry theory, hydrochloric acid is an acid that donates a proton to the water molecule.

So we can conclude that hydrochloric acid would be classified as an acid to the Arrhenius definition due to giving of hydrogen ions.

Learn more about acid here: brainly.com/question/25148363

#SPJ1

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weight is 55.06g/mol

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Doping Se with P would produce a(n) ________ semiconductor with ____________ conductivity compared to pure Se.
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4 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
In chemistry, what is the definition of the term salt? a compound consisting of an anion from an acid and a cation from a base a
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In chemistry<span>, a </span>salt<span> is an ionic compound that can be formed by the neutralization reaction of an acid and a base.So yes it is</span>
7 0
3 years ago
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Answer:

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Explanation:

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