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Stels [109]
3 years ago
7

What is one example of a molecule that is not a compound?

Chemistry
2 answers:
Marrrta [24]3 years ago
4 0
Br2 or O2 or N2 or H2 or F2 or I2 etc.
podryga [215]3 years ago
4 0

Answer:

H2 is a molecule

Explanation:

Hydrogen gas H2 is a molecule not a compound because it is made up of similar elements.

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Which is most likely to dissolve fastest in water? A. sugar cube B. powdered sugar
leva [86]
Sugar cube is my answer

Hope this helps!
Let me know if i'm wrong.
7 0
3 years ago
Read 2 more answers
How many molecules in 9.18 moles of C11H12O22
Setler [38]

Answer:

55.3 × 10²³ molecules

Explanation:

Given data:

Number of moles of C₁₁H₁₂O₂₂ = 9.18 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given data:

9.18 mol × 6.022 × 10²³ molecules /1 mol

55.3 × 10²³ molecules

5 0
3 years ago
21 Given the following acid dissociation constants, which acid has the strongest conjugate base?
Makovka662 [10]
The correct answer is HCN.
7 0
3 years ago
List the advantages and disadvantages of restricting antibioticuse
vlada-n [284]

Answer:

Advantages - less chances of developing resistant strains, less cost, less side effects, allowing the body to mount immune response

Disadvantages - inadequate/incomplete cure leading to complications, longer stay in the hospital

Explanation:

3 0
3 years ago
Consider the equilibrium: HCOOH(aq) + F-(aq) <----> HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka
Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K =  1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K =  = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .


Hope That helps!

8 0
3 years ago
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