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igor_vitrenko [27]
3 years ago
7

[20 Points] I need help with these questions:

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b"


1.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2


The given line's slope is -4, so the perpendicular line's slope is 1/4.

y = 1/4x + b

To find "b", you can plug in the point (4, -2) into the equation

y = 1/4x + b

-2 = 1/4(4) + b

-2 = 1 + b

-3 = b


y=\frac{1}{4} x-3


2.) To find "m", use the slope formula and plug in the two points:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{8-(-1)}{-2-4}

m=\frac{8+1}{-2-4}

m=\frac{9}{-6} =-\frac{3}{2}


y = -3/2x + b

Plug in one of the points to find "b"

y = -3/2x + b

-1 = -3/2(4) + b

-1 = -6 + b

5 = b


y=-\frac{3}{2}x +5


3.) y-intercept: 5 (since the given equation's y-intercept is 5)

I'm confused with what they mean by "steep", so I'll try to update this later unless someone else has an answer


So I looked it up, and it says that a steep slope is a line that is more vertical [if that makes sense]. So you could do a slope of +3 (more than 3, like 4, 5, 6...) because the given line's slope is 3, and you need a new line that is more steeper(vertical)

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