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Romashka-Z-Leto [24]
3 years ago
5

Use the Change of Base Formula to evaluate log5 92. Then convert log5 92 to a logarithm in base 3. Round to the nearest thousand

th.
Mathematics
2 answers:
ANTONII [103]3 years ago
6 0
I was thinking that the answer  could be 

2.810; log3 21.903
         
            OR


<span> 2.810; log3 55.2 </span>

So,<span> log5 of 92 is between 2.5 and 3  Correct answer is A</span>

dusya [7]3 years ago
5 0

Answer:

\log_5 92=2.809

\log_3 2.809=0.940

Step-by-step explanation:

To find : Use the Change of Base Formula to evaluate \log_5 92.

Then convert \log_5 92 to a logarithm in base 3.

Solution :

Change of Base Formula,

\log_b x=\frac{log_a x}{\log_a b}

Applying this,

\log_5 92=\frac{log 92}{\log 5}

\log_5 92=\frac{1.963}{0.698}

\log_5 92=2.809

Now, converting \log_5 92 to a logarithm in base 3

\log_3 2.809=\frac{log 2.809}{\log 3}

\log_3 2.809=\frac{0.448}{0.477}

\log_3 2.809=0.940

Therefore, The solution is \log_3 2.809=0.940

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ludmilkaskok [199]
The complete question in the attached figure

we have that
tan a=7/24    a----> III quadrant
cos b=-12/13   b----> II quadrant
sin (a+b)=?

we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
</span>
step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant

step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
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step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325

the answer is
sin (a+b)=-36/325

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