In the value 9,443.2 we can spot two 4's.
One resides in the hundreds column and the other resides in the tens column.
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Percent error : (approximate value - exact value) / exact value.....x 100
percent error : (5.75 - 6.25) / 6.25......ignore any negative signs
0.5 / 6.25 = 0.08.....x 100 = 8% error <==
Answer:
12 sides and measure of each interior angle is 150...
Answer:
Yes
Step-by-step explanation:
Given that In my data set of 10 exam scores, the mean turned out to be the score of the person with the third highest grade.
No two people got the same score.
Let the scores be a,b,c,d,e in ascending order where no two scores are equal
If a+b=d+e =2c then we can have c as the mean of the scores of 5 persons
This is because
Total sum = a+b+c+d+e = (a+b)+c+(d+e)
= 2c+c+2c=5c
Average= 5c/5 = c
It makes sense and there are chances as long as the above condition is satisfied.
