4 years ago

What is the answer to 2x^2 - 3x - 15 = 5

Mathematics

1 answer:

Alja [10]4 years ago

6 0

2x²-3x-15=5
2x²-3x-15-5=0
2x²-3x-20=0
½(2x+5)(2x-8)

-2x=-5
x=-5/2

2x-8=0
2x=8
x=4

---------------------------

You might be interested in

Solve the equation.<br> S + (-20) = -19

natima [27]

Answer:

S = 1

Step-by-step explanation:

If you add a positive 1 to -20, you would get -19

8 0

3 years ago

Read 2 more answers

Janet has 8 points after the first round of the same game. how far does she travel to get to 2 points?

dolphi86 [110]

Answer:

Step-by-step explanation:

8-2=6

answer is 6

7 0

3 years ago

Read 2 more answers

Solve the equation 5/6x - 4 = -2

Leviafan [203]

1. Add 4 to both sides of the equation.

$\frac{5}{6}x-4+4=-2+4$

$\frac{5}{6}x=2$

2. Multiply 6/5.

$\frac{6}{5} * \frac{5}{6}x = \frac{6}{5} * 2$

x= $\frac{12}{5}$

8 0

4 years ago

. Find the distance between points A and B on the graph below.

dmitriy555 [2]

U can just find the slope. From B to A it is up 8 and 3 to the right. So 8/3 which is 2.6 rounded. The answer is C

3 0

4 years ago

Without graphing, determine whether the system of linear equations has one solution, infinitely many solutions, or no solution.

Luda [366]

$\huge{ \mathcal{ \underline{ Answer} \: \: ✓ }}$

First equation :

$y = 15x + 1$

$y - 15x - 1 = 0$

Second equation :

$y = 15x + 2$

$y - 15x - 2 = 0$

Now, the equations are in the form of

$a_1x {}^{2} + b_1x + c_1 = 0$

$a_2x {}^{2} + b_2x + c_2 = 0$

where,

$\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \neq \dfrac{c_1}{c_2}$

therefore the equations would have no solution .

_____________________________

$\mathrm{ \#TeeNForeveR}$

8 0

3 years ago