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AURORKA [14]
3 years ago
7

In one hour, 17 cars drive through an intersection. Two-fifths of the 17 cars fail to come to a complete stop at the stop sign.

About how many cars do not come to a complete stop?
Mathematics
2 answers:
lutik1710 [3]3 years ago
7 0
The answer would be 7 cars
Rasek [7]3 years ago
3 0

Answer:

Step-by-step explanation:

When you have a number (17) and want to know some fraction (2/5) of that number, you should multiply the number by the fraction.

17 * (2/5)

= (17*2)/5

= 34/5

= 6.8

You can then round this number up --> about 7 cars.

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For this Prism to be a right prism, all the lateral faces must be rectangles. Is enough infromation given to prove the lateral f
Ilia_Sergeevich [38]

Answer:

yes i think that is definitely enough intonation

6 0
3 years ago
A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n
Ratling [72]

Answer:

a)

k = \dfrac{1}{21}

b) 0.476

c) 0.667    

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

P(y) = ky

a) Property of discrete probability distribution:

\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}

b) at most four forms are required

P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476

c) probability that between two and five forms (inclusive) are required

P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667

8 0
3 years ago
William went shopping for a new phone because of a sale. The store was offering a 15% discount. If the price on the tag was $41,
Damm [24]

Answer: $34.85

Step-by-step explanation: $41 x 15%= 34.85 before tax

4 0
3 years ago
X+2y=-1 and 4x-4y=20 solve by substitution
Illusion [34]

To do this problem you would first need to factor out a variable, which in this case I would want to do the first equation because it is isolated. Now the equations would look like this:

x = -2y - 1

4x - 4y = 20

Since we know that x is now equal to -2y - 1 we can plug it in to the x value in the second equation:

4 (-2y -1) - 4y = 20

-8y -4 - 4y

-12y - 4 = 20

-12y = 24

y = -2

Now that we know the y value plug the y value to one equation to find the x, I will be using the first equation

x + 2(-2) = -1

x - 4 = -1

x = 3

Solutions:

y = -2

x = 3

8 0
3 years ago
5/x+1 ÷ 6/3x+3 divide
Shalnov [3]
Here is how to work that problem out. (check the picture)

7 0
2 years ago
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