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bearhunter [10]
3 years ago
12

Write the equation of the line perpendicular to + = that passes through (−,−). Write your answer in slope-intercept form.

Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

y = 0.25x - 5

Step-by-step explanation:

Given line is 4x + y = 3

or y = -4x + 3

Comparing this with slope-intercept form y = mx + c :

slope of this line is -4

Product of slopes of perpendicular lines = -1

⇒ slope of a line perpendicular to this is \frac{-1}{-4} = \frac{1}{4} = 0.25

This line also passes through the point (-4,-6)

The equation of a line having slope m and passing through a point (h,k) is

y - k = m(x - h)

⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}

⇒ y + 6 = 0.25×(x + 4)

⇒ y + 6 = 0.25x + 1

⇒ <u>y = 0.25x - 5</u>

This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)

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In January, Music Marathon priced all the compact discs (CD’s) at $20. In February, these same CD’s were discounted 50% and in M
skad [1K]

Answer:I think it would be $9

Step-by-step explanation:

50% of 20 is $10

10% of $10 is $1

Subtract 1 from 10, which gives you $9

3 0
3 years ago
Find the measure of angle x in the figure below: (1 point) Two triangles are shown such that one triangle is inverted and share
Elena L [17]
75°+75°=150°
angles in a triangle add up to 180°
180°-150°=30°
c) x=30°
5 0
3 years ago
Can someone help me I’ll Mark brainliest I been struggling with this one :(
mariarad [96]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
3 years ago
3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10
wariber [46]

Answer:

The expected value of lateness \frac{7}{20} hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

  Lateness             P (Lateness)

  On Time                     4/5

1 Hour Late                  1/10

2 Hours Late                1/20

3 Hours Late                1/20​

The formula of expected value of a random variable is:

E(X)=\sum x\cdot P(X=x)

Compute the expected value of lateness as follows:

E(X)=\sum x\cdot P(X=x)

         =(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}

Thus, the expected value of lateness \frac{7}{20} hours.

8 0
3 years ago
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