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ivann1987 [24]
3 years ago
5

Find, to four significant digits, the distance between the graphs of 2x-3y+4=0 and 2x-3y+15=0.

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0
In analytical geometry, we can find the linear distance between two parallel lines by determining the coefficients of the variables and the constants. The general equation for a linear equation is: Ax + By = C. 

Line 1: 2x - 3y = -4
Line 2: 2x - 3y = -15

In this case, A=2 and B=-3. The constants are C₁ = -4 and C₂ = -15. The distance follows this formula:

d = |C₁ - C₂|/(√(A²+B²)
d = |⁻4 - ⁻15|/(√(2²+⁻3²)
d = 3.051 units
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What is the area of parallelogram ABCD?<br><br><br> ____ square units
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Answer:

13

Step-by-step explanation:

Here's a method of finding the area of any polygon knowing its vertices. I'm using this parallelogram as an example.

Make a table like this (each vertex with its x- and y-coordinates):

Pt    x       y

A     3      6

B     6      5

C     5      1

D     2      2

A     3      6

Now multiply each x-coordinate by the y-coordinate on the line below and write it on the right side. Bold type shows the first multiplication.

       x       y

A     3      6

B     6      5      15

C     5      1        6

D     2      2      10

A     3      6      12

Now multiply each y-coordinate by the x-coordinate on the line below and subtract from each produce you already have. Do each subtraction. Bold type shows the first multiplication.

       x       y

A     3     6

B     6      5      15 - 36 = -21

C     5      1        6 - 25 = -19

D     2      2      10 - 2 =     8

A     3      6      12 - 6 =     6

Add all the differences.

       x       y

A     3      6

B     6      5      15 - 36 = -21

C     5      1        6 - 25 = -19

D     2      2      10 - 2 =     8

A     3      6      12 - 6 =     6

                                   +____

                                       -26

The area of the polygon is the absolute value of half of the sum of the differences.

area = |-26/2| = |-13| = 13

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