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2 years ago

Sketch the area under the standard normal curve over the indicated interval and find the specified area.

Mathematics

1 answer:

Fudgin [204]2 years ago

5 0

Answer:

a) The area of the right of z=0 is P(z >0) =0.5.

b) The area of the left of z=0 is P(z < 0) =0.5.

c) The area of the left of z=-1.35 is P(z <- 1.35) =0.0885.

d) The area of the left of z=-0.48 is P(z <-0.48) =0.3156.

Step-by-step explanation:

Here are the graphs respectively.

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What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is eq

NNADVOKAT [17]

Answer:

Step-by-step explanation:

What is the length of the apothem, rounded to the nearest inch? recall that in a regular hexagon, the length of the radius is equal to the length of each side of the hexagon. 4 in. 5 in. 9 in. 11 in.

8 0

1 year ago

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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!

Marat540 [252]

Answer: The answer is 9

Step-by-step explanation:

3p + 6 = 5p − 12

3(9) + 6 = 5(9) − 12

27 + 6 = 45 − 12

33 = 33

7 0

6 months ago

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Answer both please, the topic is linear inequalities, and please explain it to me.

Bogdan [553]

Question 1 solution:
You have two unknowns here:

Let the Water current speed = W

Let Rita's average speed = R

We are given two situations, where we can form two equations, and therefore solve for the two unknowns, W, R:

Part 1) W→ , R←(against current, upstream)
If Rita is paddling at 2mi/hr against the current, this means that the current is trying to slow her down. If you look at the direction of the water, it is "opposing" Rita, it is "opposite", therefore, our equation must have a negative sign for water:

R–W=2 - equation 1

Part 2) W→ , R→(with current)
Therefore, R+W=3 - equation 2

From equation 1, W=R-2,
Substitute into equation 2.
R+(R–2)=3
2R=5
R=5/2mi/hr

So when W=0 (still), R=5/2mi/hr

Finding the water speed using the same rearranging and substituting process:

1... R=2+W
2... (2+W)+W=3
2W=1
W=1/2mi/hr

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2 years ago

Need help on this one!! plz show process

diamong [38]

Sally is 6 and Tomas is 3 so

6 +(3×2)

and 6-3

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2 years ago