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3 years ago

Sketch the area under the standard normal curve over the indicated interval and find the specified area.

Mathematics

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

a) The area of the right of z=0 is P(z >0) =0.5.

b) The area of the left of z=0 is P(z < 0) =0.5.

c) The area of the left of z=-1.35 is P(z <- 1.35) =0.0885.

d) The area of the left of z=-0.48 is P(z <-0.48) =0.3156.

Step-by-step explanation:

Here are the graphs respectively.

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A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$

Where, p is the probability of success $p=\frac{2}{7}$

q is the probability of failure q=1-p, $q=1-\frac{2}{7}=\frac{5}{7}$

n is total number of trials n=8

r=3

Substitute the values,

$P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}$

$P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}$

$P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}$

$P(X=3)=0.2428$

Therefore, the probability that 8 mice are required is 0.2428.

5 0

3 years ago

4 3/4 divided by 1 1/6

ozzi

Answer:

$2\frac{13}{22}$

Step-by-step explanation:

$=\frac{19}{4}\div \frac{11}{6}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{19}{4}\times \frac{6}{11}$

$=\frac{19}{2}\times \frac{3}{11}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{19\times \:3}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:19\times \:3=57$

$=\frac{57}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22$

$=\frac{57}{22}$

$=2\frac{13}{22}$

5 0

2 years ago

Let f(x) = ............

34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

Now lets solve for f(-2)

-2^2-3

4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

3 0

3 years ago

Directions: Find the complemen

andre [41]

Given:

The angles are:

Example $54^\circ$

1. $63^\circ$

2. $87^\circ$

3. $45^\circ$

4. $72^\circ$

5. $5^\circ$

To find:

The complimentary angle of the given angles.

Solution:

If two angles are complimentary, then their sum is 90 degrees.

Example: Let x be the complimentary angle of $54^\circ$ , then

$x+54^\circ=90^\circ$

$x=90^\circ -54^\circ$

$x=36^\circ$

Similarly,

1. The complimentary angle of $63^\circ$ is:

$90^\circ -63^\circ=27^\circ$

2. The complimentary angle of $87^\circ$ is:

$90^\circ -87^\circ=3^\circ$

3. The complimentary angle of $45^\circ$ is:

$90^\circ -45^\circ=45^\circ$

4. The complimentary angle of $72^\circ$ is:

$90^\circ -72^\circ=18^\circ$

5. The complimentary angle of $5^\circ$ is:

$90^\circ -5^\circ=85^\circ$

Therefore, the complimentary angles of $54^\circ, 63^\circ, 87^\circ, 45^\circ, 72^\circ, 5^\circ$ are $36^\circ, 27^\circ, 3^\circ, 45^\circ, 18^\circ, 85^\circ$ respectively.

6 0

3 years ago

What is 4xy-3xz+y-2x-5=

netineya [11]

Answer:

xz+y-2x-5

Step-by-step equation

You can only combine like terms

3 0

2 years ago