Check the picture below.
Sketch the area under the standard normal curve over the indicated interval and find the specified area.
1 answer:
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See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
