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laiz [17]
3 years ago
15

Which of the following statements could be translated to the equation n-5=-2?

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

The difference between a number and five is negative two.

Step-by-step explanation:

n-5=difference between a number and five

=-2 means is negative two

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Alisiya [41]
Answer:

Explanation:

19.

P = 2(x - 3 + 7x + 1)
= 2(8x - 2)
= 16x - 4

20.

P = 3y + 5 + y - 4 + 6y
= 10y + 1
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500 grams of quarters
ohaa [14]

Answer:

0.04409 quarter

Step-by-step explanation:

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2 years ago
What is the sum? (2x + 4)/(x + 1) + (- x + 5)/(x + 1) (x - 1)/(x + 1) (1 - 1)/(2x + 2) (x + 9)/(x + 1) (x + 9)/(2x + 2)
butalik [34]

Answer:

Step-by-step explanation:

Since they already have a common denominator of x+1 we can add the numerators

(2x+4-x+5)/(x+1)

(x+9)/(x+1)

4 0
3 years ago
Can someone please help me with these math problems ASAP?!<br> Thanks in advance! ;)
Mamont248 [21]

Answer:

11) Here given Function,

f(x) = \sqrt{2x-11}

And, g(x) = -|0.1|x+5

For f(x) = g(x)

\sqrt{2x-11}=-|0.1|x+5

2x-11=(-|0.1|x+5)^2

2x-11=0.01x^2 - 10|0.1|x+25

2x=0.01x^2 - 10|0.1|x+25+11

2x=0.01x^2 - 10|0.1|x+36

0.01x^2 - 10|0.1|x - 2x+36=0

When we solve this equation,

We found,

 x = 12.5227 ≈ 12.53

Thus, the required solution is, x = 12.53

12) Here the height of rocket A in x second,

f(x) = -16x^2+74x+9

And, The height gain by the rocket B in x seconds,

g(x) = -16x^2+82x

If at x seconds both A and B gain the same height,

That is, f(x) = g(x)

⇒ -16x^2+74x+9= -16x^2+82x

⇒74x + 9 = 82x

⇒ 82x - 74x = 9

⇒ 8x = 9

⇒ x = 1.125 ≈ 1.13

Thus, the required solution is x = 1.13 seconds (approx)


4 0
3 years ago
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0
3 years ago
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