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Anettt [7]
3 years ago
14

If you start with a number divide it by 4 then multiply it by two you end up with 8 squared

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

8 squared = 64

so

(x/4)*2 = 64

divide x/4 by 2 to get x/2=64

 now multiply both sides by 2 to get x=128

x = 128



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VikaD [51]
What is the question asking for?
5 0
3 years ago
Can you have an 'All Real Numbers' solution for inequalities? If so, give an example.
irga5000 [103]

Answer:

yes

Step-by-step explanation:

x+7>x+3

7 0
3 years ago
What are the solutions to the equation 2(x-3)^2=54 ?
erastova [34]

Answer:

      x =(6-√108)/2=3-3√ 3 = -2.196

 x =(6+√108)/2=3+3√ 3 = 8.196

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

2 • (x - 3)2 - 54 = 0

Step  2  :

 2.1    Evaluate :  (x-3)2   =  x2-6x+9 

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   2x2 - 12x - 36  =   2 • (x2 - 6x - 18) 

Adding  9  has completed the left hand side into a perfect square :

   x2-6x+9  =

   (x-3) • (x-3)  =

  (x-3)2  (x-3)1 =

   x-3

Now, applying the Square Root Principle to  Eq. #4.3.1  we get:

   x-3 = √ 27

Add  3  to both sides to obtain:

   x = 3 + √ 27

Since a square root has two values, one positive and the other negative

   x2 - 6x - 18 = 0

   has two solutions:

  x = 3 + √ 27

   or

  x = 3 - √ 27

Solve Quadratic Equation using the Quadratic Formula

 4.4     Solving    x2-6x-18 = 0 by the Quadratic Formula .

 According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

            - B  ±  √ B2-4AC

  x =   ————————

                      2A

  In our case,  A   =     1

                      B   =    -6

                      C   =  -18

Accordingly,  B2  -  4AC   =

                     36 - (-72) =

                     108

Applying the quadratic formula :

               6 ± √ 108

   x  =    —————

                    2

Can  √ 108 be simplified ?

Yes!   The prime factorization of  108   is

   2•2•3•3•3 

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 108   =  √ 2•2•3•3•3   =2•3•√ 3   =

                ±  6 • √ 3

  √ 3   , rounded to 4 decimal digits, is   1.7321

 So now we are looking at:

           x  =  ( 6 ± 6 •  1.732 ) / 2

Two real solutions:

 x =(6+√108)/2=3+3√ 3 = 8.196

or:

 x =(6-√108)/2=3-3√ 3 = -2.196

7 0
3 years ago
Omar has decided to purchase an $11,000 car. He plans on putting 20% down toward the purchase, and financing the rest at 4.8% in
Solnce55 [7]

Answer:

The monthly payment is $262.95

Step-by-step explanation:

* Lets explain how to solve the problem

- Omar has decided to purchase an $11,000 car

- He plans on putting 20% down toward the purchase

* Lets find the value of the 20%

∵ The principal value is $11000

∴ the value of the 20% = 20/100 × 11000 = 2200

∴ He will put $2200 down

* Lets find the balance to be paid off on installments

∴ The balance = 11000 - 2200 = 8800

- He financing the rest at 4.8% interest rate for 3 years

* Lets find the rule of the monthly payment

∵ pmt=\frac{\frac{r}{n}[P(1+\frac{r}{n})^{nt}]}{(1+\frac{r}{n})^{nt}-1} , where

- pmt is the monthly payment

- P = the investment amount

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested or borrowed for

∵ P = 8800

∵ r = 4.8/100 = 0.048

∵ n = 12

∵ t = 3

∴ pmt=\frac{\frac{0.048}{12}[8800(1+\frac{0.048}{12})^{3(12)}]}{(1+\frac{0.048}{12})^{3(12)}-1}

∴ pmt=\frac{0.004[8800(1.004)^{36}]}{(1.004)^{36}-1}=262.95

* The monthly payment is $262.95

8 0
3 years ago
Yx*2; use x=7,And y=2
Mars2501 [29]

Answer:

14*2

Step-by-step explanation:

x=7 and Y=2

2×7*2

14*2

7 0
3 years ago
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