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erma4kov [3.2K]
3 years ago
9

Find the equation of the parabola whose vertex is the origin and whose directrix is x=-4

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0
The standard form of equation of parabola is (x-h)^2=4p(y-k) where the directrix is y=k-p and the vertex is as point (h,k).
Thus given that the vertex is at (0,0)
y=k-p
the value of p will be:
-4=0-p
p=4
thus the equation will be:
(x-0)^2=4*4(y-0)
x^2=16y
hence;
y=1/16x^2
the answer is y=1/16x^2
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one solution

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It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help​
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Answer:

505/19

Step-by-step explanation:

Easy

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Solve for n -3n-5=16
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Answer:

n = -7

Step-by-step explanation:

Solve for n:

-3 n - 5 = 16

Hint: | Isolate terms with n to the left-hand side.

Add 5 to both sides:

(5 - 5) - 3 n = 5 + 16

Hint: | Look for the difference of two identical terms.

5 - 5 = 0:

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Hint: | Evaluate 16 + 5.

16 + 5 = 21:

-3 n = 21

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -3 n = 21 by -3:

(-3 n)/(-3) = 21/(-3)

Hint: | Any nonzero number divided by itself is one.

(-3)/(-3) = 1:

n = 21/(-3)

Hint: | Reduce 21/(-3) to lowest terms. Start by finding the GCD of 21 and -3.

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n = 7/(-1)

Hint: | Simplify the sign of 7/(-1).

Multiply numerator and denominator of 7/(-1) by -1:

Answer: n = -7

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