In chemistry, there is a class of compounds called alkanes. They have the general formula 2x+2, where stands for a carbon

pls help me guys may brainlest,5 star,1 heart,at follow kayo saakin pag nasagot miyo ito 3 questions lang naman po ito eh1.mitch

Natalija [7]

Answer:

a. 1/2 + 9/10 = 5/10+9/10 = 14/10 = 7/5 = 1 2/5 meters or ribbon

b. 5/8 = 15/24, 7/12 = 14/24 Jeff jogged longer and by 1/24 kilometers

c. 3/9 = 6/18. 15/18-6/18 = 9/18 = 1/2 left.

Hope this helps :)

Step-by-step explanation:

3 0

1 year ago

One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained

Reptile [31]

Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

The expected value of a negative binomial is the reciprocal of its success probability p.

E(X)=1/p

At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

E(X)=1/p

E(X1)=1

After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (p=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

E(X)=E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

E(X)=1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

E(X)= 29.29

Note: Those values in E(X), should be written the way it will in standard algebra ie they should be small.

4 0

2 years ago

What is 0.7 divided by 792

Dvinal [7]

0.7/729 equals 0.00088383838

6 0

2 years ago

Read 2 more answers

What is the area of a sector with a central angle of \frac{5 \pi }{6} radians and a diameter of 5.6 in.? Use 3.14 for π and roun

kvasek [131]

Answer:

10.26 in²

Step-by-step explanation:

The area (A) of the sector is

A = area of circle × fraction of circle

= πr² × $\frac{\frac{5\pi }{6} }{2\pi }$

= π × 2.8² × $\frac{5}{12}$ ≈ 10.26 in²

7 0

2 years ago

Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan

White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0

2 years ago