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3 years ago

Solve the following system of equations 2x+y=11 and -x+2y=2

Mathematics

1 answer:

givi [52]3 years ago

7 0

{2x+y=11
{-x+2y=2 //*2

{2x+y=11
+
{-2x+4y=4

5y=15
y=3
-x+6=2
x=4
Answer
x=4; y=3

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Find element a13 of matrix A, if A=

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2 years ago

The ratio of the number of Miki's stickers to the number of Ken's

Lera25 [3.4K]

Answer:

Miki had 288 stickers and Ken had 252 stickers.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

Miki has x stickers.

Ken has y stickers.

The ratio of the number of Miki's stickers to the number of Ken's stickers was 8:7.

This means that $\frac{x}{y} = \frac{8}{7}$ , that is: $7x = 8y$ , or $x = \frac{8y}{7}$

After Miki gave Ken 18 of her stickers, they had the same number of stickers.

This means that:

$x - 18 = y + 18$

$x - y = 36$

Since $x = \frac{8y}{7}$

$\frac{8y}{7} - y = 36$

$\frac{8y}{7} - \frac{7y}{7} = 36$

$\frac{y}{7} = 36$

$y = 36*7 = 252$

And

$x - y = 36$

$x = 36 + y = 36 + 252 = 288$

Miki had 288 stickers and Ken had 252 stickers.

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2 years ago

How do you adjust a quotient?

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2 years ago

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1 year ago

Haynes High School chartered buses for 60 students to go on a field trip. Valley High School chartered buses for 80 students.

Svetradugi [14.3K]

Answer: $20

Step-by-step explanation:

Let 'x' be the cost of a ticket at Haynes

Let 'y' be the cost of a ticket at Valley

Since the total cost from both schools are the same, we can write it as:

$60x=80y$

Since the cost of tickets at Valley was $5 less than Haynes, we can write it as:

$y=x-5$

Now we have two equations, we can use to substitute into the other expression:

$60x=80y$

$60x=80(x-5)$ we substitute y in this equation with the other equation

$60x=80x-400$

$-20x =-400$

$x = 20$

Therefore the cost of the ticket at Haynes is $20 and the cost of the ticket at Valley is $15.

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1 year ago