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Yakvenalex [24]
2 years ago
15

SOMEONE PLEASE HELP ME I WILL GIVE YOU BRAINLY

Mathematics
1 answer:
Ivanshal [37]2 years ago
7 0

Step-by-step explanation:

a scatter plot with no association

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At Garcia's Bike Rentals, it costs $13 to rent a bike for 3 hours. How many dollars does it cost per hour of bike use?
Naily [24]

Answer:

$4.33

Step-by-step explanation:

3 hours -> $13

1 hour -> $13/3 = $4.33

5 0
3 years ago
Which expression represents a factorization of 63 − 18?\
Evgesh-ka [11]

Answer:

8

Step-by-step explanation:

5+5=20

7 x 1 =78

78=9090

90900-5967=5676

harry should end with 5 tomatoes

4 0
3 years ago
Could someone help me please ​
Alexxx [7]

1. 3x+9-9=18-9      

3x=9

x=3

2. 4x-12=20

4x-12+12=20+12

4x=32

x=8

3. x+0-0

x=0

4. x/2-2+2=9+2

x/2=11

(2)(x/2)=11(2)

x=22

5. 12x-21=3

12x-21+21=3+21

12x=24

x=2

6. 3x-15=18

3x-15+15=18+15

3x=33

x=11

7. 3x-25=14

3x-25+25=14+25

x=13

8. 3x+16=22

3x+16-16=22-16

x=2

9. 2x-8=2

2x-8+8=2+8

2x=10

x=5

10. 9x-18=9

9x-18+18=9+18

9x=27

x=3

11. x+0=0

x=0

12. 9x-8=19

9x-8+8=19+8

9x=27

x=3

If  you want to check my answers

use substitution method by using the x into for each equation.

7 0
3 years ago
Read 2 more answers
What property does the statement show? (4x8)x3=(8x4)x3
8090 [49]
Why not? Because every math system you've ever worked with has obeyed these properties! You have never dealt with a system where a×b did not in fact equal b×a, for instance, or where (a×b)×c did not equal a×(b×c). Which is why the properties probably seem somewhat pointless to you. Don't worry about their "relevance" for now; just make sure you can keep the properties straight so you can pass the next test. The lesson below explains how I kept track of the properties.
6 0
3 years ago
In how many ways can the letters in the word MATHEMATICS be reshuffled so that all consonants appear together?
steposvetlana [31]

Answer:

75600

Step-by-step explanation:

We are given that  a word MATHEMATICS

Total letters =11

M repeated 2 times

T repeated 2 times

A repeated 2 times

Total vowels=4

Let MTHMTCS=P

Total number of ways in which MTHMTCS can be arranged=\frac{7!}{2!2!}

PAEAI

Total number of ways in which PAEAI can arranged=\frac{5!}{2!}

Total number of arrangements when all consonant appear together=\frac{7!}{2!2!}\times \frac{5!}{2!}

Total number of arrangements when all consonant appear together=\frac{7!5!}{2\times 2\times 2}=\frac{7\times 6\times 5\times 4\times 3\times 2\times 1\times 5\times 4\times 3\times 2\times 1}{8}=75600

By using formula ;n!=n(n-1)(n-2)...2\times 1

4 0
3 years ago
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