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3 years ago

Simplify 1/9-1/x 1/81-1/x^2

Mathematics

1 answer:

tekilochka [14]3 years ago

5 0

$\cfrac{ \frac{1}{9}- \frac{1}{x} }{ \frac{1}{81} - \frac{1}{x^2} }= \cfrac{ \frac{x-9}{9x} }{ \frac{x^2-81}{81x^2} }= \cfrac{x-9}{9x}* \cfrac{81x^2}{(x-9)(x+9)}= \cfrac{9x}{x+9}$

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Es urgente ¡¡¡ si la MH de a y 4 es 6 y la MH de 8 y b es 12 calcula la MH de a y b

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Answer:

Sabemos que:

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Con esto podemos encontrar el valor de a:

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