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xxTIMURxx [149]
3 years ago
7

Simplify 1/9-1/x 1/81-1/x^2

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0
\cfrac{ \frac{1}{9}-  \frac{1}{x} }{ \frac{1}{81} - \frac{1}{x^2} }=  \cfrac{ \frac{x-9}{9x} }{ \frac{x^2-81}{81x^2} }=  \cfrac{x-9}{9x}* \cfrac{81x^2}{(x-9)(x+9)}= \cfrac{9x}{x+9}
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Answer:

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Step-by-step explanation:

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