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Andrew [12]
3 years ago
10

Solve the system of functions below: -9x = (-2x^2)-4-y x = (-y+6)/3

Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

Point Form:

(1,3) (5,-9)

Equation Form:

x=1 y=3

x=5 y=-9

solve for the first variable in one of the equations, then substitute the result into the other equation.

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Free points everyone<br><br>45 + 45 + 90​
klasskru [66]
<h2>Answer:</h2>

<u><em>Thank you for the free points!</em></u>

<u><em>45 + 45 = 90</em></u>

<u><em>45 + 45 + 90 = 180</em></u>

<h2>Step-by-step explanation:</h2>

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3 years ago
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Yuliya22 [10]
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5 0
3 years ago
A helicopter leaves bristol and flies due east for 10 miles.Then the helicopter flies 8miles north before landing. What is the d
DedPeter [7]

Answer:

The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>

Step-by-step explanation:

Given:

Helicopter flies 10 miles east of bristol.

Then the helicopter flies 8 miles North before landing.

To find the direct distance between the helicopter and bristol.

Solution:

In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter

The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.

On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.

Applying Pythagorean theorem to find the hypotenuse of the triangle.

Hypotenuse^2=Short\ leg^2+Shortest\ leg^2

Hypotenuse^2=10^2+8^2

Hypotenuse^2=100+64\\Hypotenuse^2=164

Taking square root both sides.

\sqrt{Hyptenuse^2}=\sqrt{164}\\Hypotenuse = 12.81\ miles

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles

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3 years ago
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2 years ago
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