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lara31 [8.8K]
3 years ago
8

Why would you copy an individual instead of listing that name on the To line?

Computers and Technology
2 answers:
Eva8 [605]3 years ago
5 0

Answer

When the person is not directly involved in the message but has a need to know about it.

Explanation

Even though the person really doesn't need the information in your correspondence, and you don't expect him to answer you or take any action, you still want him to know that you're doing your job, and how you're handling this matter, and you want him to have the information available if he wants to see it.


kvv77 [185]3 years ago
3 0

When you send a letter or an email to somebody in the course
of your job, you might copy your boss.  Even though he really
doesn't need the information in your correspondence, and you
don't expect him to answer you or take any action, you still want
him to know that you're doing your job, and how you're handling
this matter, and you want him to have the information available
IF he wants to see it.

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Lapatulllka [165]

Answer:

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3 years ago
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Identify the flaws / limitations in the following ConvertToNumber method:
lions [1.4K]

Answer:

Flaws and limitations identified in this program includes;

1.There was a not necessary usage of variable retrieval. Would have made use of canConvert.

2. Looking at the program, one will notice numerous typos. One of which is the fact that in JAVA we make use of Boolean instead of bool.

3.We rather use Integer.parseInt in JAVA and not Int16, cant make use of Int16.

4. The exception cant be printed

5. JAVA makes use of checkConversion instead of convertNumber as used in the program.

6. It cant work for decimal numbers, 0 and big integers.

Explanation:

See Answer for the detailed explaination of the flaws and limitations identified in the program.

4 0
3 years ago
Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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