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Margarita [4]
3 years ago
14

A business analyst makes $20 an hour for the first 42 hours he works during a week and $28 an hour for each hour worked over 42

hours. Which piecewise equation models his total weekly pay y in dollars as it relates to the number of hours x that he has worked during the week?
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
3 0

The piecewise function for this should be f(x) \left \{ {{y = 20x, x < 42} \atop {y = 28x + 840, x > 42}} \right..

We can find the first equation simply. He gets 20 every hour up to 42 hours. Therefore, the function gives us our first equation of y = 20x when x < 42.

The second one, we must know what the base amount he would make before starting to make 28 an hour. The 28 an hour would be 28x, but he would have already made 840 before hand. Which we can determine by multiplying the base of 42 hrs by 20.

42 * 20 = 840.

mezya [45]3 years ago
3 0

  the answer is 840 . your welcome

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Read 2 more answers
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

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